All categories

4 years ago

Put one digit 1,0,3,7

Mathematics

1 answer:

Stells [14]4 years ago

4 0

Ok so I don't really know how to explain this well except that you have to mess around with the numbers to see what divides to 43. I tried things like 103÷7, and 107÷3. It's a little bit easier since you can't divide by zero (so don't try something like 731÷0) and if you divide by one, you'll just get the same answer (like 307÷1=307) . This eliminates a lot of your number combinations.
I found out that 301÷7 gives you the magic number of ...43!!! I hope this makes sense to you, if it doesn't, let me know :D.

You might be interested in

What 34,920 rounded to the ten thousand and // 850,471 rounded to hundred thousands

CaHeK987 [17]

Answer is 30000 and 900000

4 0

3 years ago

Read 2 more answers

50 POINTS!!

Mrrafil [7]

Answer:

none of the above

Step-by-step explanation:

the answer is -3/4

8 0

3 years ago

Read 2 more answers

What is the first term of the sequence below? ___1, 5,25,125

gtnhenbr [62]

Answer:

The first term of the sequence is 1/5

Step-by-step explanation:

The first term is 1/5.

The reason is that there is a common ratio between each term. In this case multiplying the previous term in the sequence by 5 would give the next term.

So in this case 1/5 is the first term.

If we multiply 1/5 by 5, it will give the next term which is 1.

1/5*5=1

Thus the first term in the sequence = 1/5....

6 0

3 years ago

Find the following product if possible. Explain if it is not possible. <br><br> (See picture)

Nataly_w [17]

Answer:

The answer to your question is the letter a

Step-by-step explanation:

| 1 4 -1 | | 2 -1 |

| 3 2 2 | | 0 3 | Product = 2 x 3 and 3 x 2 = 2 x 2

| 5 2 | It is possible to do this product,

the result will be a 2 x 2 matrix

Process

1.- Multiply first row by first column and second row by second column.

2.- Multiply the second row by the first column and second row by the second column.

= (1 x 2) + (4 x 0) + (-1 x 5) = 2 + 0 - 5 = -3

= (1 x -1) + (4 x 3) + (-1 x 2) = -1 + 12 - 2 = 9

= (3 x 2) + (2 x 0) + (2 x 5) = 6 + 0 + 10 = 16

= (3 x -1) + (2 x 3) + (2 x 2) = -3 + 6 + 4 = 7

Result

| 3 9 |

| 16 7 |

4 0

4 years ago

The box plots compare the number of calories in each snack pack of crackers and cookies.

Nikitich [7]

Answer:

4th statement is true.

Step-by-step explanation:

We have been two box plots, which represents the number of calories in each snack pack of crackers and cookies. We are asked to find the correct statement about our given box plots.

1. More packets of crackers have 80 calories than any other number of calories.

We can see that median of box plot representing calories of cookies is 80. This means that half of the packets of crackers have less than 80 calories and half of the packets have more than 80 calories, therefore, 1st statement is false.

2. The value 70 is an outlier for the number of calories in the cookie pack.

Since an outlier is 1.5 times the interquartile range.

$IQR=Q_3-Q_1$

$\text{IQR of cookie packs}=105-90$

$\text{IQR of cookie packs}=15$

$\text{Lower outlier}=Q_1-(1.5*IQR)$

$\text{Lower outlier}=90-(1.5*15)$

$\text{Lower outlier}=90-22.5$

$\text{Lower outlier}=67.5$

Since any number less than 67.5 will be an outlier and 70 is grater than 67.5, therefore, 70 is not an outlier in number of calories in cookie packs and 2nd statement is false.

3. The upper quartile of the cookie data is equivalent to the maximum in the cracker data.

We can see that upper quartile of cookie data is 105 and the maximum in cracker data is 100. Since 105 is greater than 100, therefore, 3rd statement is false.

4. The number of calories in each pack of cookies has a greater variation than the number of calories in each pack of crackers.

Since range and IQR are good measures of variation of box-plots, so we will find the range and IQR of our both box-plots.

We have already seen that IQR of cookie packs is 15.

$\text{IQR of cracker packs}=85-75$

$\text{IQR of cracker packs}=10$

$\text{Range}=\text{Maximum value - Minimum value}$

$\text{Range of calories in cracker packs}=100-70$

$\text{Range of calories in cracker packs}=30$

$\text{Range of calories in cookie packs}=115-70$

$\text{Range of calories in cookie packs}=45$

We can see that the range of calories in cookie packs (45) is greater than range of calories in cracker packs (30) and IQR of calories in cookie packs (15) is greater than IQR of calories in cracker packs (10), therefore, 4th statement is true.

3 0

4 years ago

Read 2 more answers