1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aliya0001 [1]
4 years ago
5

Put one digit 1,0,3,7

Mathematics
1 answer:
Stells [14]4 years ago
4 0
Ok so I don't really know how to explain this well except that you have to mess around with the numbers to see what divides to 43. I tried things like 103÷7, and 107÷3. It's a little bit easier since you can't divide by zero (so don't try something like 731÷0) and if you divide by one, you'll just get the same answer (like 307÷1=307) . This eliminates a lot of your number combinations.
I found out that 301÷7 gives you the magic number of ...43!!! I hope this makes sense to you, if it doesn't, let me know :D.
You might be interested in
Jenny and Chris share some prize money in the ratio 2:4. The prize money totaled $3000. How much did Chris win?
mafiozo [28]
Solution for What is 2.4 percent of 3000:

2.4 percent *3000 =

(2.4:100)*3000 =

(2.4*3000):100 =

7200:100 = 72
Maybe i dont know tbh
6 0
3 years ago
Pls help I will give brainliest
miss Akunina [59]

Answer:

Step-by-step explanation:

the distance around the figure--we need to find the perimeter

we have rectangle that has the side, 8 and 15

P(r)=2(8)+2(15)=16+30=46

we also have half of the circle with the diameter =8 and r=4

Circumference =2*3.14*r

C=2*3.14*4=25.12

we need just half of the circle 25.12/2=12.56

P figure=46+12.56=58.56

Area= rectangle=l*w=8*15=120

Area(circle)=3.14*r^2=3.14*16=50.24

half circle 50.24/2=25.12

Area figure=120+25.12=145.12

6 0
3 years ago
Can someone please help me with this math problem.
mr Goodwill [35]
PART A:
Find the rate of change between 1980 and 1989
d for P₁ = 80 - 60
d for P₁ = 20

d for P₂ = 76 - 82
d for P₂ = -6

The rate of change in P₁ is 20 hundred per year. The rate of change in P₂ is -6 hundred per year.

PART B:
Find the rate of change between 1989 and 1996
d for P₁ = 100 - 80
d for P₁ = 20

d for P₂ = 70 - 76
d for P₂ = -6

The rate of change in P₁ is 20 hundred per year. The rate of change in P₂ is -6 hundred per year.

PART C:
Find the rate of change between 1980 and 1996
d for P₁ = 100 - 60
d for P₁ = 40

d for P₂ = 70 - 82
d for P₂ = -12

The rate of change in P₁ is 40 hundred per year. The rate of change in P₂ is -12 hundred per year.
4 0
4 years ago
Another one plz help
Nostrana [21]

Answer:

the answer is the 3rd one

3 0
3 years ago
Read 2 more answers
I need Help. I will give brainliest/
Len [333]

Answer:

the answer is 48.

there is no any answer to hundred

Step-by-step explanation:

we know that,

area of parellelogram=base×height

base=8cm,height=6cm

so, 8×6=48

hope it helps

3 0
3 years ago
Read 2 more answers
Other questions:
  • Kyra is building a dollhouse. The carpet for the bedroom is 27 square inches.The length of the bedroom is 6 inches. How long is
    11·1 answer
  • ∠ABC = ___?___ <br> a) ∠MNP<br> b) ∠PMN <br> c) ∠ NPM<br> d) ∠NMP
    11·2 answers
  • Customer arrivals at a bank are random and independent; the probability of an arrival in any one-minute period is the same as th
    7·1 answer
  • Alternate exterior angles ​
    6·1 answer
  • Imagine you are a financial analyst at an investment bank. According to your research of publicly-traded companies, 60% of the c
    13·1 answer
  • Find the total amount given the original price and tip rate. Round to the nearest cent if necessary. Original price: $41.32 Tip:
    11·1 answer
  • HELP ASAP!! Justify the answer to the equation by explaining the steps you took.
    11·1 answer
  • Help plsssssssssssssssssssssss I will give brainliest if right
    14·2 answers
  • The sum of three numbers is 8. The third is 9
    13·1 answer
  • Need help with this question. only need help with A.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!