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Tasya [4]
3 years ago
5

What are facts about a cylinder

Mathematics
2 answers:
nataly862011 [7]3 years ago
6 0
Cylinders are three dimensional. They do not have any vertices. An example of a cylinder is a soup can.
Norma-Jean [14]3 years ago
5 0
A cylinder has no sides and has only two faces top and bottom
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Solve the inequality 13 > 3x + 1
Ivenika [448]
4 > x

step by step explanation:

13 > 3x + 1
-1 -1
12 > 3x
/3 /3
4 > x
3 0
3 years ago
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I need help in this . Just ignore that equation in top of the problem
GuDViN [60]
Communtative property
5 0
4 years ago
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How do I solve question 6 through 8?<br> Solve for me
rewona [7]

The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

<h3>How to determine the functions?</h3>

A quadratic function is represented as:

y = a(x - h)^2 + k

<u>Question #6</u>

The vertex of the graph is

(h, k) = (-1, 2)

So, we have:

y = a(x + 1)^2 + 2

The graph pass through the f(0) = -2

So, we have:

-2 = a(0 + 1)^2 + 2

Evaluate the like terms

a = -4

Substitute a = -4 in y = a(x + 1)^2 + 2

y = -4(x + 1)^2 + 2

<u>Question #7</u>

The vertex of the graph is

(h, k) = (2, 1)

So, we have:

y = a(x - 2)^2 + 1

The graph pass through (1, 3)

So, we have:

3 = a(1 - 2)^2 + 1

Evaluate the like terms

a = 2

Substitute a = 2 in y = a(x - 2)^2 + 1

y = 2(x - 2)^2 + 1

<u>Question #8</u>

The vertex of the graph is

(h, k) = (1, -2)

So, we have:

y = a(x - 1)^2 - 2

The graph pass through (0, -3)

So, we have:

-3 = a(0 - 1)^2 - 2

Evaluate the like terms

a = -1

Substitute a = -1 in y = a(x - 1)^2 - 2

y = -(x - 1)^2 - 2

Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

Read more about parabola at:

brainly.com/question/1480401

#SPJ1

5 0
2 years ago
Let V be the volume of the solid obtained by rotating about the y-axis the region bounded y = 4x and y = x2/4 . Find V by slicin
aliya0001 [1]

Answer:

Step-by-step explanation:

Consider the graphs of the y = 4x  and  y = \frac{x^{2} }{4}.

By equating the expressions, the intersection points of the graphs can be found and in this way delimit the area that will rotate around the Y axis.

4x = \frac{x^{2} }{4} \\   x^{2}  = 16x \\ x^{2}  - 16x = 0 \\   x(x-16) = 0 then x=0  o  x=16. Therefore the integration limits are:

y = 4(0) = 0  and  y = 4(16) = 64

The inverse functions are given by:

x = 2 \sqrt{y}  and  x = \frac{y}{4}. Then

The volume of the solid of revolution is given by:

\int\limits^{64}_ {0} \, [2\sqrt{y} - \frac{y}{4}]^{2}  dy = \int\limits^{64}_ {0} \, [4y - y^{3/2} + \frac{y^{2}}{16} ]\  dy = [2y^{2} - \frac{2}{5}y^{5/2} + \frac{y^{3}}{48} ]\limits^{64}_ {0} = 546.133 u^{2}

6 0
4 years ago
Pleasee anyonnee help me assaaapppp
nekit [7.7K]
30, 34
You add 4 on
44
Because it starts at 10 and 10 cannot be divided by 4
7 0
3 years ago
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