Answer:
There was a 1.93% probability of having multiples (twins or more) in 1980.
Step-by-step explanation:
There were 3,612,258 births in the US in 1980.
Of those,
68339 + 1337 = 69676 were multiplies.
So
What was the probability of having multiples (twins or more) in 1980?

There was a 1.93% probability of having multiples (twins or more) in 1980.
Answer:
wow
Step-by-step explanation:
153.952848723
509 goes into 78362 153.952848723 times.
This is a case of exponential growth. The appropriate equation, with the given data inserted, is P(t) = 500 ( 1+0.15)^50
or = 500 (1.15)^50
Evaluate this on your calculator.
So to do this, we have to get rid of one of the variables by adding or subtracting the two equations together.
I will get rid of y. So, we can multiply the second equation by 2. This gives us
2x-2y=10
Now, we can add both equations
This gives us 7x=-14
Therefore, x = -2
Plug that into another equation.
-10 + 2y=-24
Therefore, y = -7
Hope this helped!! :D