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Answer:
We can conclude that the experimental course effective at the alpha = 0.05 level of significance.
Step-by-step explanation:
Let p be the proportion of students from experimental course who complete the course with a letter grade of A, B, or C. Null and alternative hypotheses are:
H_0: p = 0.45
H_1: p > 0.45
Test statistic can be found using the equation
where
- p(s) is the sample proportion of students enrolled experimental course and complete with a letter grade of A, B, or C (
)
- p is the success proportion assumed under null hypothesis. (0.45)
- N is the sample size (20)
Then ≈4.045
Since the <em>one tailed</em> 19 <em>degrees of freedom </em>p-value is ≈0.0003<0.05 we can conclude that the experimental course effective at the alpha = 0.05 level of significance.