Answer:
a. V = (20-x)
b . 1185.185
Step-by-step explanation:
Given that:
- The height: 20 - x (in )
- Let x be the length of a side of the base of the box (x>0)
a. Write a polynomial function in factored form modeling the volume V of the box.
As we know that, this is a rectangular box has a square base so the Volume of it is:
V = h *
<=> V = (20-x)
b. What is the maximum possible volume of the box?
To maximum the volume of it, we need to use first derivative of the volume.
<=> dV / Dx = -3
+ 40x
Let dV / Dx = 0, we have:
-3
+ 40x = 0
<=> x = 40/3
=>the height h = 20/3
So the maximum possible volume of the box is:
V = 20/3 * 40/3 *40/3
= 1185.185
Answer:
∠3 = 107°
Step-by-step explanation:
Similar to the other question, ∠3 and ∠4 are supplementary and add up to 180 degrees as they make up the entirety of a straight line.
∠4 is 73°, so ∠3 has to be 107°.
Volume = 9in • 9in • 9in
Volume = 729 in^3
Now multiply the volume by 6 grams.
Let H = total weight of the cube in terms of grams.
H = V • 6
H = 729 • 6
H = 4,374 grams
Where is the proof you need help with?