30 treadmills to 36 elliptical machines the ratio in simplest form

1 answer:

4 0

30 treadmills : 36 ellipticals
this could be written in a few ways, but i am going to write it as a fraction. since treadmills come first, you put 30/36.

now that you have your fraction you have to find the GCF (greatest common factor) of the two numbers. the GCF is 6, so you have to divide 30 treadmills by 6, and 36 ellipticals by 6.
30/6=5
36/6=6

5/6 or 5:6 is the simplified ratio of treadmills to ellipticals

comment for any questions!!

You might be interested in

(5+x)x=36 what is x?

lana [24]

X=4

The only way you can go about doing this is by finding the factors of 36 (1, 2, 3, 4, 6, 9, 12, 18, 36) and then seeing which pair make sense.

In this case, 9 and 4.

So, plug in the numbers so it makes sense.

(5+4)4=36

5+4=9
9*4=36

8 0

3 years ago

Read 2 more answers

5 POINTS !! ANSWER FASTTT

MariettaO [177]

N= 2

Substitute 2 in for n in expression

=(5 + n) ÷ (n - 1)
=(5 + 2) ÷ (2 - 1)
=7 ÷ 1
=7

If n= 2, the expression equals 7.

Hope this helps! :)

3 0

3 years ago

The line integral of xydx×x^2y^3dy where c is the triangle with points (0,0) (1,0) (1,2) using green's theorem

lyudmila [28]

If $\mathcal C$ is the boundary of the triangle $D$ , then by Green's theorem

$\displaystyle\int_{\mathcal C}xy\,\mathrm dx+x^2y^3\,\mathrm dy=\iint_D\left(\frac{\partial(x^2y^3)}{\partial x}-\frac{\partial(xy)}{\partial y}\right)\,\mathrm dA$
$=\displaystyle\int_{x=0}^{x=1}\int_{y=0}^{y=2x}(2xy^3-x)\,\mathrm dy\,\mathrm dx$
$=\displaystyle\int_{x=0}^{x=1}x\int_{y=0}^{y=2x}(2y^3-1)\,\mathrm dy\,\mathrm dx$
$=\displaystyle\int_{x=0}^{x=1}x(8x^4-2x)\,\mathrm dx=\frac23$