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Andrej [43]
2 years ago
5

The line integral of xydx×x^2y^3dy where c is the triangle with points (0,0) (1,0) (1,2) using green's theorem

Mathematics
1 answer:
lyudmila [28]2 years ago
4 0
If \mathcal C is the boundary of the triangle D, then by Green's theorem

\displaystyle\int_{\mathcal C}xy\,\mathrm dx+x^2y^3\,\mathrm dy=\iint_D\left(\frac{\partial(x^2y^3)}{\partial x}-\frac{\partial(xy)}{\partial y}\right)\,\mathrm dA
=\displaystyle\int_{x=0}^{x=1}\int_{y=0}^{y=2x}(2xy^3-x)\,\mathrm dy\,\mathrm dx
=\displaystyle\int_{x=0}^{x=1}x\int_{y=0}^{y=2x}(2y^3-1)\,\mathrm dy\,\mathrm dx
=\displaystyle\int_{x=0}^{x=1}x(8x^4-2x)\,\mathrm dx=\frac23
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A1 = 9 × 1 - 6 = 3

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Step-by-step explanation:

Σ ( 9n - 6 ) , n = 1

An = general term.

let Σ (An) = Σ (9n-6)

An = 9n-6

to determine the terms, plug in the value of n into the general term(An)

If you're asked for the 1st term then n = 1

if you're asked for the 2nd term then n = 2. and so forth.

To find the 1st 4 terms, just plug in 1 up to 4 into n bit by bit.

An = 9n - 6

A1 = 9 × 1 - 6 = 3

A2 = 18 - 6 = 12

A3 = 27 - 6 = 21

A4 = 36 - 6 = 30. done.

write the terms from 1 to 4 like this :

{ A1, A2, A3, A4 } = { 3, 12, 21, 30 }.

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Step-by-step explanation:

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