Complete the equation that describes c, the number of cats and g, the number of gold bars put into the machine.

Mathematics

1 answer:

babunello [35]3 years ago

6 0

Answer:

C= 3g

Step-by-step explanation:

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The function f(x) is graphed below. What is true about the graph on the interval from x=−∞ to x=a?

xxMikexx [17]

Answer:

The correct answer for the question that is being presented above is this one: "The range of the function is all real numbers; The function has two x-intercepts. The statements about the graph of the function f(x) = 2x2 – x – 6 that are true includes: The range of the function is all real numbers; The function has two x-intercepts.

Step-by-step explanation:

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Evaluate the expression 3.14(a2 + ab) when a = 4 and b = 3. (Input decimals only, such as 12.71, as the answer.)

Natasha2012 [34]

Answer:

87.92

Step-by-step explanation:

3.14(a² + ab) where a = 4 and b = 3

Plug the given numbers into the appropriate values. Remember to follow PEMDAS.

3.14((4)² + (4)(3))

3.14(16 + 12)

3.14(28)

87.92

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3 years ago

[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation

irina1246 [14]

Answer:

$y=-\frac{158}{579}$

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

$A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]$

And the vector B is formed with the solution of each equation of the system: $b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]$

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called $A_{2}$ .

$A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]$

The value of y using Cramer's rule is:

$y=\frac{det(A_{2}) }{det(A)}$

Find the value of the determinant of each matrix, and divide:

$y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}$