Complete the equation that describes c, the number of cats and g, the number of gold bars put into the machine.

Which is equivalent to 23·2-5? A) 2-15 B) 2-8 Eliminate C) 2-2 D) 22

bulgar [2K]

2^3 * 2^-5 = 2^(3 + (-5) = 2^(3 - 5) = 2^-2

4 0

3 years ago

You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.

postnew [5]

This problem seems to be wrong because no minimum point was found and no point of landing exists

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

Derivatives

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

1)

The function provided in the question is

$h(x)=2x^2-12x+20$

Let's find the first derivative

$h'(x)=4x-12$

solving h'=0:

$4x-12=0$

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

2)

To find when will the ball land, we set h=0

$2x^2-12x+20=0$

Simplifying by 2

$x^2-6x+10=0$

Completing squares

$x^2-6x+9+10-9=0$

Factoring and rearranging

$(x-3)^2=-1$

There is no real value of x to solve the above equation, so the ball will never land.

This problem seems to be wrong because no minimum point was found and no point of landing exists

3 0

3 years ago

Slope of the line that passes through points (-3,4) and (5,-1)

Veronika [31]

When hav epoins (x1,y1) and (x2,y2)
slope is (y2-y1)/(x2-x1)

(-3,4) and (5,-1)
slope=(-1-4)/(5-(-3))=-5/(5+3)=-5/8

slope=-5/8

6 0

3 years ago

The manager of a snack bar buys bottled water in packs of 35 and candy bars in packs of 20. Then, she sells the items individual

hoa [83]

Answer:

8 packs of bottled water and 14 packs of candy bars

Step-by-step explanation:

Provided,

Each pack of water bottles = 35 bottles

Each pack of candy = 20 candy

Since quantity of candy in each pack is small than quantity of water bottle in each pack, in order to have same quantity in numbers of both bottles and candies,

Purchase quantity of candy packs shall be more than the pack of water bottles.

Further, with this option 1 and 2 are not valid as candy packs are same or less than packs of water bottle.

In option 3 and 4, option 3 have smaller quantities as provided manager bought the least possible quantity.

Accordingly

Option 3

8 packs of water bottle = $8 \times 35 = 280 \ water\ bottles$