Answer:
47052806.5418
Step-by-step explanation:
Honestly I just used a calculator...
Hope this helped tho
17 bc it's in the middle (btw I didn't make that up my teacher in 6th grade said that)
Answer:
No, the equation is not a linear equation.
Step-by-step explanation:
There is the x^2 thing that doesn't make it a linear equation.
Answer:
110 test
Step-by-step explanation:
Let
x ----> the number of packet of 10 test
y ----> the total cost
we know that
The number of packet of 10 test purchase multiplied by $11 plus the enrollment fee of $30 must be equal to $151
so
The linear equation that represent this scenario is
![y=11x+30](https://tex.z-dn.net/?f=y%3D11x%2B30)
we have
![y=\$151](https://tex.z-dn.net/?f=y%3D%5C%24151)
substitute
![151=11x+30](https://tex.z-dn.net/?f=151%3D11x%2B30)
Solve for x
subtract 30 both sides
![11x=151-30](https://tex.z-dn.net/?f=11x%3D151-30)
![11x=121](https://tex.z-dn.net/?f=11x%3D121)
Divide by 11 both sides
![x=11](https://tex.z-dn.net/?f=x%3D11)
The number of packets purchase was 11
To find out the number of test, multiply the number of packets by 10
![11(10)=110\ test](https://tex.z-dn.net/?f=11%2810%29%3D110%5C%20test)