There are 6 questions in this plz don't answer if you don't have an answer best answer gets branlyest worth 100

Write an equation in a point-slope form that passes through the given point with the given slope (3, 5), m = -4 and-1, 8), m = ½

4vir4ik [10]

Answer:

$\large\boxed{y-5=-4(x-3)}\\\boxed{y-8=\dfrac{1}{2}(x+1)}$

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

$m=-4,\ (3,\ 5)\\\\y-5=-4(x-3)$

$m=\dfrac{1}{2},\ (-1,\ 8)\\\\y-8=\dfrac{1}{2}(x-(-1))\\\\y-8=\dfrac{1}{2}(x+1)$

8 0

3 years ago

What is the final amount of $105.00 that is put into a savings account with 8% interest rate for 25 years, if the interest is co

Tema [17]

A=105×(1+0.08÷4)^(4×25)
A=760.68

7 0

3 years ago

Read 2 more answers

A sample of blood pressure measurements is taken for a group of adults, and those values (mm Hg) are listed below. The values

nika2105 [10]

Answer:

For systolic pressure data:

$\bar X =127.2\\\\S=17.91668\\\\CV=\frac{17.91668}{127.2}=0.14085$

For diastolic pressure data:

$\bar X =73.5\\\\S=12.54\\\\CV=\frac{73.5}{12.54}=0.17061$

Systolic pressure is slightly less variable, among individuals in the sample, than diastolic pressure.

Step-by-step explanation:

The coefficient of variation is defined as the percentage relative variation of a set of data with respect to its average. And it is calculated like this:

$CV=\frac{\bar X}{S}$

$S =\sqrt{\frac{1}{n-1} \sum_{i=1}^n (x_i-\bar{x})^2$

$\bar X={\frac{1}{n} \sum_{i=1}^n x_i$

For systolic pressure data:

$\bar X =127.2\\\\S=17.91668\\\\CV=\frac{17.91668}{127.2}=0.14085$

For diastolic pressure data:

$\bar X =73.5\\\\S=12.54\\\\CV=\frac{12.54}{73.5}=0.17061$

It is observed that the systolic pressure shows greater standard deviation but less coefficient of variation. This is due to the greater magnitude of its measurement scale.

Systolic pressure is slightly less variable, among individuals in the sample, than diastolic pressure.

7 0

3 years ago

In a recent survey in a Statistics class, it was determined that only 74% of the students attend class on Fridays. From past dat

Anna007 [38]

Answer:

a) 83%

b) 0.892

Step-by-step explanation:

percentage that attends class on friday = 74%

percentage that pass because they attend class on friday = 88%

percentage that pass but did not go to school on friday = 20%

a) percentage of students expected to pass the course

= (74% x 88%) +(88% x 20%)

= 0.6512 + 0.176

= 0.8272

= 83%

b) If a person passes the course, what is the probability that he/she attended classes on Fridays

= 74% divided by 83%

= 0.892

7 0

3 years ago

What is 231 divided by 42

luda_lava [24]

5.5 is the answer for the problem

6 0

3 years ago

Read 2 more answers