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Bond [772]
3 years ago
7

give an example of a convergent infinite series whose sum equal 3/5. explain how you know your series converges and write out wo

rk to show that its sum is in fact 3/5
Mathematics
1 answer:
krek1111 [17]3 years ago
5 0

Answer:

The series 1/5, 2/15, 4/45, 8/135... converges and sums up to 3/5

Step-by-step explanation:

Consider the infinite geometric series

1/5, 2/15, 4/45, 8/135...

With first term, a=1/5

common ratio, r = ⅔

The series converge because the common ratio, |r|<1.

The sum to infinity of a geometric series, S= a/(1-r)

S= 1/5 ÷ (1-⅔) = 1/5 ÷ 1/3 = 3/5

Therefore, the geometric series 1/5, 2/15, 4/45, 8/135... sums up to 3/5.

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Find the polynomial of lowest degree with only real coefficients and having the given zeros. -7i and square root of 2
mario62 [17]

Answer:

x³ - (√2)x² + 49x - 49√2

Step-by-step explanation:

If one root is -7i, another root must be 7i.  You can't just have one root with i.  The other roos is √2, so there are 3 roots.  

x = -7i       is one root,

   (x + 7i) = 0    is the factor

x = 7i       is one root

  (x - 7i) = 0     is the factor

x = √2      is one root

    (x - √2) = 0   is the factor

So the factors are...

(x + 7i)(x - 7i)(x - √2) = 0

Multiply these out to find the polynomial...

(x + 7i)(x - 7i) =  x² + 7i - 7i - 49i²

Which simplifies to

  x² - 49i²        since i² = -1 , we have

    x² - 49(-1)  

 

      x² + 49

Now we have...

(x² + 49)(x - √2) = 0

Now foil this out...

 x²(x) - x²(-√2) + 49(x) + 49(-√2) = 0

     x³ + (√2)x² + 49x - 49√2

7 0
3 years ago
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