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jolli1 [7]
4 years ago
12

Graph the equations to solve the system y= x+4 y= -x-6

Mathematics
1 answer:
AVprozaik [17]4 years ago
3 0

You can plot lines by extrapolating two points and connecting them. To extrapolate points on the graph, choose whatever value for x you like, and calculate the correspondent y value.

Line y = x+4:

\text{choose } x=0 \implies y = 0+4 =4 \implies (0,4) \text{ is on the line}

\text{choose } x=1 \implies y = 1+4 =5 \implies (1,5) \text{ is on the line}

Line y = -x-6:

\text{choose } x=-3 \implies y = -(-3)-6 =-3 \implies (-3,-3) \text{ is on the line}

\text{choose } x=-6 \implies y = -(-6)-6 =0 \implies (-6,0) \text{ is on the line}

Now draw the first two points (0,4) and (1,5) and connect them. You have the first line. Draw the last two points (-3,-3) and (-6,0) and connect them. You have the second line.

You should find out that the two lines cross at (-5,-1)

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<u>Step-by-step explanation:</u>

Use the following conversions:

1 hour = 60 minutes

2 cups = 1 pint

2 pints = 1 quart

1 ton = 2000 pounds

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3 years ago
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Answer:

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Step-by-step explanation:

5 0
3 years ago
What’s the answer to this math problem?v
olga2289 [7]

Answer:

The correct answer is D. AB ≅ WX

Step-by-step explanation:

No other choice involves a pair of congruent/similar lines. If the figure is rotated clockwise, you could transpose one over the other and AB would overlay WX exactly.

7 0
3 years ago
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a st
Alinara [238K]

Answer:

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so \mu = 0.5, \sigma = 0.05.

What is the probability that a line width is greater than 0.62 micrometer?

That is P(X > 0.62)

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.62 - 0.5}{0.05}

Z = 2.4

Z = 2.4 has a pvalue of 0.99180.

This means that P(X \leq 0.62) = 0.99180.

We also have that

P(X \leq 0.62) + P(X > 0.62) = 1

P(X > 0.62) = 1 - 0.99180 = 0.0082

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

3 0
3 years ago
What is the expression on -1/64
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Answer:

The expression of ideas or feelings is the showing of them through words, actions, or artistic activities. ... Your expression is the way that your face looks at a particular moment. It shows what you are thinking or feeling. Levin sat there, an expression of sadness on his face.

Step-by-step explanation:


7 0
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