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Nookie1986 [14]
3 years ago
5

I need an answer asap

Mathematics
1 answer:
allsm [11]3 years ago
8 0

Answer:

yes

no

no

yes

Step-by-step explanation:

You might be interested in
2x + y = 15 x + y = 10​
Artyom0805 [142]

Answer:

2x+y=15x+y=10

Consider the first equation. Subtract 15x from both sides.

2x+y−15x=y

Combine 2x and −15x to get −13x.

−13x+y=y

Subtract y from both sides.

−13x+y−y=0

Combine y and −y to get 0.

−13x=0

Divide both sides by −13. Zero divided by any non-zero number gives zero.

x=0

Consider the second equation. Insert the known values of variables into the equation.

15×0+y=10

Multiply 15 and 0 to get 0.

0+y=10

Anything plus zero gives itself.

3 0
2 years ago
One yard is equal to three feet. Which expression represents the number of feet for any given number of yards? A. x-3 B. 3 • x C
Marysya12 [62]
The answer is B. For every yard there are 3 feet.
7 0
3 years ago
The marked price of an article is Rs 400. If 5% discount is allowed, how much should
kow [346]

Answer:

Rs.380

Step-by-step explanation:

Given data

Price=  Rs 400.

Discount= 5%

Let us find the amount of the discount

=5/100*400

=0.05*400

=Rs. 20

Hence the amount that should be paid for it is

=400-20

=Rs.380

7 0
3 years ago
Find the length of the height of the right trapezoid shown below, if it has the greatest possible area and its perimeter is equa
Artyom0805 [142]

Answer:

The height of the right trapezoid is   \frac{6}{5+\sqrt{3}}\ units

Step-by-step explanation:

Let

x ----> the height of the right trapezoid in units

we know that

The perimeter of the figure is equal to

P=AB+BC+CD+DH+HA

we have

P=6\ units

AB=BC=CH=HA=x ---> because is a square

substitute

6=x+x+CD+DH+x

6=3x+CD+DH -----> equation A

<em>In the right triangle CDH</em>

sin(30\°)=\frac{CH}{CD}

sin(30\°)=\frac{1}{2}

so

Remember  that CH=x

\frac{1}{2}=\frac{x}{CD}

CD=2x

tan(30\°)=\frac{CH}{DH}

tan(30\°)=\frac{\sqrt{3}}{3}

so

\frac{\sqrt{3}}{3}=\frac{x}{DH}

DH=x\sqrt{3}

substitute the values in the equation A

6=3x+CD+DH -----> equation A

CD=2x

DH=x\sqrt{3}

6=3x+2x+x\sqrt{3}

6=5x+x\sqrt{3}

6=x[5+\sqrt{3}]

x=\frac{6}{5+\sqrt{3}}\ units

5 0
3 years ago
What is f(2) for f(x)=2x^4-5x^2-3x+2
zysi [14]
2(2^4) - 5(2^2) - 3*2 + 2 = 32-20-6+2 = 8
8 0
3 years ago
Read 2 more answers
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