Question

Divide (-7x+x^2+15)\(-3+x)

Answer 1

The answer would be x-4+ 3/x-3

Answer 2

Answer:

The result becomes:

$x-4+\frac{3}{x-3}$

Step-by-step explanation:

The given expression in correct order is :

$\frac{x^{2}-7x+15 }{x-3}$

Now, dividing the leading coefficients of the numerator and divisor we get

$\frac{x^{2} }{x}=x$

So, quotient is x

Multiplying $x-3$ by x

=>$x^{2} -3x$

Subtracting $x^{2} -3x$ from $x^{2} -7x+15$ we get $-4x+15$

This is the new remainder.

Now, the given equation becomes: $x+\frac{-4x+15}{x-3}$

Dividing the leading coefficients we get $\frac{-4x}{x}=-4$

Multiplying $x-3$ bu -4 to get $-4x+12$

Subtracting $-4x+12$ from $-4x+15$ = 3

This 3 is the new remainder.

Now, the equation becomes: $-4+\frac{3}{x-3}$

Therefore, the result becomes:

$x-4+\frac{3}{x-3}$