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Alexxandr [17]
2 years ago
13

What is the equation of a line that passes through the point (1, 8) and is perpendicular to the line whose equation is y=x/2+3 ?

Mathematics
1 answer:
Serhud [2]2 years ago
3 0

Answer:

The equation of the line would be y = -2x + 10

Step-by-step explanation:

In order to find the equation of this line, we first have to note that perpendicular lines have opposite and reciprocal slopes. Therefore, since the original line has a slope of 1/2, we know the new line will have a slope of -2. Now we can use that information along with the given point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 8 = -2(x - 1)

y - 8 = -2x + 2

y = -2x + 10

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Answer:

→ The table is:

→  x  →  -1   →  0  →  1

→  y  →  -3  →  0  →  3

The graph of the line is figure d

Step-by-step explanation:

∵ y = 3x

∵ x = -1, 0, 1

→ Substitute the values of x in the equation to find the values of y

∴ y = 3(-1) = -3

∴ y = 3(0) = 0

∴ y = 3(1) = 3

→ The table is:

→  x  →  -1   →  0  →  1

→  y  →  -3  →  0  →  3

∵ The form of the linear equation is y = m x + b, where

  • m is the slope
  • b is the y-intercept

∵ y = 3x

→ Compare the equation with the form

∴ m = 3

∴ b = 0

→ That means the slope is positive, then the direction of the line must

   be from left tp right and passes through the origin

∴ The graph of the line is figure d

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2 years ago
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