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Sever21 [200]
3 years ago
7

What is Anita's speed rounded to the nearest hundredth Anita's speed is 0.277

Mathematics
1 answer:
mash [69]3 years ago
8 0
Anita's speed rounded to the nearest hundredth is 0.28. The first 7 in the number 0.277 is the hundredths place. You look at the second 7 and you can see that 7 is greater than 5. So the answer is 0.28.
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Use the features on the left to identify which of the following are binomial experiments.
soldi70 [24.7K]

i want to say its (C) but it might also be (B)

3 0
3 years ago
Read 2 more answers
A 16 kg bag of watermelon for $8 per kg
Zarrin [17]
To solve this all we need to do is multiply. 

Since 1 kg is for $8, then we will multiply to see how much 16 kg would be for.

16 × 8 = 128

So, 16 kg is for $128. 

Hope I helped ya!!!!
8 0
3 years ago
Write the equation of the line parallel to Y equals 2/3X +1 through the point (0,-4)  use slope intercept form
Andrew [12]

Writing the slope-intercept form of a linear equation, we have:

y=mx+b

Where m is the slope and b is the y-intercept.

Since parallel lines have the same slope, we can see that the slope of the line y = 2/3x + 1 is equal m = 2/3, so for our equation we also have m = 2/3.

Now, using the point (0, -4), we have:

\begin{gathered} y=\frac{2}{3}x+b \\ (0,-4)\colon \\ -4=\frac{2}{3}\cdot0+b \\ b+0=-4 \\ b=-4 \end{gathered}

So our equation is:

y=\frac{2}{3}x-4

y = 2/3x - 4

7 0
1 year ago
A data set includes 103 body temperatures of healthy adult humans having a mean of 98.9degreesf and a standard deviation of 0.67
trasher [3.6K]

Answer:

Step-by-step explanation:

Confidence interval is written in the form,

(Sample mean - margin of error, sample mean + margin of error)

The sample mean, x is the point estimate for the population mean.

Margin of error = z × s/√n

Where

s = sample standard deviation = 0.67

n = number of samples = 103

From the information given, the population standard deviation is unknown hence, we would use the t distribution to find the z score

In order to use the t distribution, we would determine the degree of freedom, df for the sample.

df = n - 1 = 103 - 1 = 102

Since confidence level = 99% = 0.99, α = 1 - CL = 1 – 0.99 = 0.01

α/2 = 0.01/2 = 0.005

the area to the right of z0.005 is 0.005 and the area to the left of z0.005 is 1 - 0.005 = 0.995

Looking at the t distribution table,

z = 2.6249

Margin of error = 2.6249 × 0.67/√103

= 0.173

Confidence interval = 98.6 ± 0.173

This suggests that the mean body temperature could very possibly be

98.6degrees°F.

3 0
3 years ago
What is 20% of 95? (show all work)
elena-s [515]
<span>we know that if 95 is out of 100%, we can write it down as 95 = 100%. w</span><span>e also know that x is 20% of the output value, so we can write it down as x = 20%. </span>
now we have the equations:
95=100%
x=20%
next we will put the equations together
95/x = 100%/20%
95/x=100/20
<span>(95/x)*x=(100/20)*x      
</span>we multiply both sides of the equation by x
<span>95=5*x      
</span>now we divide both sides of the equation by 5 to get x
<span>95/5=x </span>
<span>19=x </span>
x=19
we now know that <span>20% of 95 = 19
let me know if you have any other questions
:)</span>
6 0
3 years ago
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