1: 3/4 2: 6/8 I’m pretty sure is the answer sorry if I’m wrong
Standardised z score = (16.075 - 16) / 0.2 = 0.375
which gives a probability of 0.1462 for selecting a package of weight 16.075
the probability of weight being excess of 16.075 = 0.5 - 0.1462 = 03538
Probability of picking 16 in excess of 16-075 = 0.3538^16 = 6.0273 * 10^-8
Original price of the laptop = P = $600
Rate of depreciation = r = 10% = 0.10
Time in years = t = 2
We have to find the worth of the laptop after 2 years. The given formula is:
Using the given values, we get:
Thus, the laptop will worth $486 in two years
Okay, so basically we have:
w as width; and 6+w as length
Perimeter=2w+2l
just substitute it with the values of width and length
P=2w+2(6+w)
P=2w+12+2w
P=4w+12
So, the answer is letter B.
462,093 round to the nearest ten thousand is 60,000 because 2 is less and 6 is greater so 6 stay the same
