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Kryger [21]
3 years ago
10

The length of an object is measured as 65.8 centimeters what is this measurement in scentific notation

Mathematics
1 answer:
julsineya [31]3 years ago
7 0

Answer:

6.58 x 10^1

Step-by-step explanation:

This is because the exponent 1 means that you have to move the decimal place in 6.58 to the right once which makes the standard form 65.8. And vice versa, if you move the decimal place to the left once in 65.8, then the answer is 6.58 x 10^1.

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Find the measure of angle JCA if J is the incenter of the triangle ABC
melamori03 [73]
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7 0
3 years ago
If the growth rate of bacteria at any time t is proportional to the number present at t and triples in 1 week
serg [7]

The population after 20 weeks will be 403.42x_{0} in which x_{0} is the initial population.

Given that the growth rate of bacteria at any time t is proportional to the number present at t and triples in 1 week.

We are required to find the number of bacteria present after 10 weeks.

let the number of bacteria present at t is x.

So,

dx/dt∝x

dx/dt=kx

1/x dx=k dt

Now integrate both sides.

\int\limits {1/x} \, dx=\int\limits{k} \, dt

log x=kt+log c----------1

Put t=0

log x_{0}=0 +log c    (x_{0} shows the population in beginning)

Cancelling log from both sides.

c=x_{0}

So put c=x_{0} in 1

log x=kt+log x_{0}

log x=log e^{kt}+log x_{0}

log x=log e^{kt}x_{0}

x=e^{kt}x_{0}

We have been given that the population triples in a week so we have to put the value of x=2x_{0} and t=1 to get the value of k.

2x_{0}=e^{k} x_{0}

2=e^{k}

log 2=k

We have to now put the value of t=20 and k=log 2 ,to get the population after 20 weeks.

x=e^{20log 2}x_{0}

x=e^{0.30*2}x_{0}

x=e^{6}x_{0}

x=403.42x_{0}

Hence the population after 20 weeks will be 403.42x_{0} in which x_{0} is the initial population.

Learn more about growth rate at brainly.com/question/25849702

#SPJ4

The given question is incomplete as the question incudes the following:

Calculate the population after 20 weeks.

5 0
2 years ago
A jar contained 8 balls: 6 red, 1 green and 1 blue. We randomly take a ball out of the jar. Once a ball is selected we do not pu
Oxana [17]

Answer:

35

Step-by-step explanation:

Given that :

Number of balls = 8

Red (R) = 6 ; 1 green(G) ; 1 BLUE (B)

Possibilities unt a blue ball is picked :

B, RB, GB, RRB, RGB, GRB, G

Draw 1 = B = 1

Draw 2 = B = 2C1 = 2

Draw 3 = B = 3C2 = 3

Draw 4 = B = 3C3 + 3C1 = 1 + 3 = 4

Draw 5 = B = 4C4 + 4C1 = 1 + 4 = 5

Draw 6 = B = 5C5 + 5C1 = 1 + 5 = 6

Draw 7 = B = 6C6 + 6C1 = 1 + 6 = 7

Draw 8 = B = 6C6 + 6C1 = 1 + 6 = 7

Taking the sum:

(1 + 2 + 3 + 4 + 5 + 6 + 7 + 7) = 35

There are 35 elements in the sample space

8 0
3 years ago
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