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PSYCHO15rus [73]
3 years ago
12

Which logarithmic function has a y-intercept?

Mathematics
1 answer:
Komok [63]3 years ago
7 0
Hello
the <span>logarithmic function has a y-intercept is :
</span><span>A. f(x) = log(x + 1) – 1
</span>if x=0 : f(0) =log(0+1)-1 =log(1)-1=0-1=-1
the graph has a y-intercept  in A(0 ; -1)
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Given the following parallelogram: Solve for x.<br> 7x + 70<br> 16x - 20
kirill115 [55]

Answer:

x=10

Step-by-step explanation:

7x+70=16x-20

70=9x-20

9x=90

x=10

8 0
3 years ago
What is (12-2i) (5+3i) multiplied?
Ilya [14]
= 12*5 + 12*3i - 5*2i - 6i^2    (remember that i^2 = -1) so:-

= 60 +26i - 6*(-1)

= 60 + 26i + 6

= 66 + 26i
5 0
3 years ago
Is (0,0) a solution to this system?
Anuta_ua [19.1K]

Answer:

option-B

Step-by-step explanation:

we are given system of inequality as

y\leq x^2-4

y>2x-1

now, we can check solution

At (0,0):

we can plug x=0 and y=0

and check inequality

0\leq 0^2-4

0\leq -4

so, this is FALSE

now, we can check second inequality

0>2\times 0-1

0>-1

So, this is TRUE

so, option-B

5 0
3 years ago
Read 2 more answers
What is the absolute value of -22
Bond [772]
The absolute value of a number is always positive. It is the distance the number is away from zero.
|-22| = 22
8 0
3 years ago
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Given the function f(x)=3x+5a / x^2-a^2 find the value of a for which f'(12) = 0
maria [59]
The function, as presented here, is ambiguous in terms of what's being deivded by what.  For the sake of example, I will assume that you meant

           3x+5a
<span> f(x)= ------------
</span>          x^2-a^2

You are saying that the derivative of this function is 0 when x=12.  Let's differentiate f(x) with respect to x and then let x = 12:

             (x^2-a^2)(3) -(3x+5a)(2x)
f '(x) = ------------------------------------- = 0 when x = 12
                [x^2-a^2]^2

(144-a^2)(3) - (36+5a)(24)
------------------------------------  =  0
               [   ]^2

Simplifying,

(144-a^2) - 8(36+5a) = 0

144 - a^2 - 288 - 40a = 0

This can be rewritten as a quadratic in standard form:

-a^2 - 40a - 144 = 0, or a^2 + 40a + 144 = 0.

Solve for a by completing the square:

a^2 + 40a + 20^2 - 20^2 + 144 = 0
        (a+20)^2    = 400 - 144 = 156

        Then a+20 = sqrt[6(26)] = sqrt[6(2)(13)] = 4(3)(13)= 2sqrt(39)

         Finally, a = -20 plus or minus 2sqrt(39)

You must check both answers by subst. into the original equation.  Only if the result(s) is(are) true is your solution (value of a) correct.
6 0
3 years ago
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