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Volgvan
3 years ago
13

Given the binomials (x - 3), (x - 1), (x + 2), and (x + 3), which one is a factor of f(x) = 2x3 + 3x2 - 2x - 3?

Mathematics
2 answers:
Ganezh [65]3 years ago
4 0
We are given the function f(x) = 2x3 + 3x2 - 2x - 3 and is asked for the factor from the given (x - 3), (x - 1), (x + 2), and (x + 3). We just have to substitute the factor to the function and find out which one is equal to zero. in this case, the answer is (x-1). 
spayn [35]3 years ago
3 0

Answer:

(x-1) is factor of our function.

Step-by-step explanation:

We are given a function f(x)=2x^{3} +3x^{2} -2x-3 and we are asked to find the correct factor from the given options.

Let us factor out our polynomial.

2x^{3} +3x^{2} -2x-3

x^{2} (2x+3)-1(2x+3)

(x^{2} -1)(2x+3)

(x+1)(x-1)(2x+3)

Therefore, (x-1) is correct choice for factor of our polynomial.



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7 and 8.

Step-by-step explanation:

When we check out what is √49 and √64, we can see that they equal 7 and 8 respectively. Since √56 is between √49 and √64, we can say that √56 is between 7 and 8.

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2 years ago
The endpoints of EF<br> are E(1,3) and F(-2,8).<br> Find EF.
Phantasy [73]

Answer:

EF = \sqrt{34} ≈ 5.83

Step-by-step explanation:

Calculate EF using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = E(1, 3) and (x₂, y₂ ) = F(- 2, 8)

EF = \sqrt{(-2-1)^2+(8-3)^2}

    = \sqrt{(-3)^2+5^2}

    = \sqrt{9+25}

    = \sqrt{34} ≈ 5.83 ( to 2 dec. places )

8 0
3 years ago
The national average sat score (for verbal and math) is 1028. if we assume a normal distribution with standard deviation 92, wha
elena55 [62]

Let X be the national sat score. X follows normal distribution with mean μ =1028, standard deviation σ = 92

The 90th percentile score is nothing but the x value for which area below x is 90%.

To find 90th percentile we will find find z score such that probability below z is 0.9

P(Z <z) = 0.9

Using excel function to find z score corresponding to probability 0.9 is

z = NORM.S.INV(0.9) = 1.28

z =1.28

Now convert z score into x value using the formula

x = z *σ + μ

x = 1.28 * 92 + 1028

x = 1145.76

The 90th percentile score value is 1145.76

The probability that randomly selected score exceeds 1200 is

P(X > 1200)

Z score corresponding to x=1200 is

z = \frac{x - mean}{standard deviation}

z = \frac{1200-1028}{92}

z = 1.8695 ~ 1.87

P(Z > 1.87 ) = 1 - P(Z < 1.87)

Using z-score table to find probability z < 1.87

P(Z < 1.87) = 0.9693

P(Z > 1.87) = 1 - 0.9693

P(Z > 1.87) = 0.0307

The probability that a randomly selected score exceeds 1200 is 0.0307

5 0
3 years ago
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