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alexandr402 [8]
2 years ago
10

of the 200 guests thay attended a party,132 brought a present for the host .what percent of the guests broight a present ?

Mathematics
1 answer:
nordsb [41]2 years ago
5 0
132/ 200 = .66
66 percent of guests brought a present.
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Math help pls, will reward lol, thanks
Ahat [919]

Answer:

see explanation

Step-by-step explanation:

Given f(x) then f(x - 2) represents a horizontal translation of f(x) shifted 2 units to the right, thus

The marked points on f(x) → f(x - 2) are

(0, 0 ) → (2, 0 )

(2, 4 ) → (4, 4 )

(3, 9 ) → (5, 9 )

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3 years ago
Graph the function by making a table of values which table is correct
Talja [164]

It is often more convenient to evaluate a polynomial when it is written is "Horner form."

... f(x) = (((10x -4)x -8)x +3)x -6

The graphs offered can be distinguished by their values of f(1) and f(2), so our table can be a short one.

... f(1) = (((10·1 -4)1 -8)1 +3)1 -6 = -5 . . . . . . . eliminates graph d

... f(2) = (((10·2 -4)2 -8)2 +3)2 -6 = 96 . . . . eliminates graphs a and c

The appropriate choice is b.

3 0
3 years ago
Driving at a constant speed, Daisy drove 360 miles in 6 hours. How many miles would she drive in 10 hours?
alexgriva [62]

Answer:

600

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2 years ago
Read 2 more answers
Rockwell hardness of pins of a certain type is known to have a mean value of 50 and a standard deviation of 1.2.a. If the distri
zalisa [80]

Answer:

a

 P(\= X \ge 51 ) =0.0062

b

P(\= X \ge 51 ) = 0

Step-by-step explanation:

From the question we are told that

The mean value is \mu = 50

The standard deviation is  \sigma = 1.2

Considering question a

The sample size is  n = 9

Generally the standard error of the mean is mathematically represented as

      \sigma_x = \frac{\sigma }{\sqrt{n} }

=>   \sigma_x = \frac{ 1.2 }{\sqrt{9} }

=>  \sigma_x = 0.4

Generally the probability that the sample mean hardness for a random sample of 9 pins is at least 51 is mathematically represented as

      P(\= X \ge 51 ) = P( \frac{\= X - \mu }{\sigma_{x}}  \ge \frac{51 - 50 }{0.4 } )

\frac{\= X -\mu}{\sigma }  =  Z (The  \ standardized \  value\  of  \ \= X )

     P(\= X \ge 51 ) = P( Z  \ge 2.5 )

=>   P(\= X \ge 51 ) =1-  P( Z  < 2.5 )

From the z table  the area under the normal curve to the left corresponding to  2.5  is

    P( Z  < 2.5 ) = 0.99379

=> P(\= X \ge 51 ) =1-0.99379

=> P(\= X \ge 51 ) =0.0062

Considering question b

The sample size is  n = 40

   Generally the standard error of the mean is mathematically represented as

      \sigma_x = \frac{\sigma }{\sqrt{n} }

=>   \sigma_x = \frac{ 1.2 }{\sqrt{40} }

=>  \sigma_x = 0.1897

Generally the (approximate) probability that the sample mean hardness for a random sample of 40 pins is at least 51 is mathematically represented as  

       P(\= X \ge 51 ) = P( \frac{\= X - \mu }{\sigma_x}  \ge \frac{51 - 50 }{0.1897 } )

=> P(\= X \ge 51 ) = P(Z  \ge 5.2715  )

=>  P(\= X \ge 51 ) = 1- P(Z < 5.2715  )

From the z table  the area under the normal curve to the left corresponding to  5.2715 and

=>  P(Z < 5.2715  ) = 1

So

   P(\= X \ge 51 ) = 1- 1

=> P(\= X \ge 51 ) = 0

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2 years ago
Barbara wants to buy some glittery heart-shaped beads to make friendship bracelets. The beads she wants come in a small pack wit
AleksAgata [21]

Answer:

I feel u

Step-by-step explanation:u need help too

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