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My name is Ann [436]
4 years ago
11

4/3 = -6e - 5/3 what is e

Mathematics
1 answer:
Illusion [34]4 years ago
7 0
6e=-5/3-4/3. 6e=-9/3. 6e=-3. e=-3/6. e=-1/2.
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Factorise 5x + 40 <br> 7x - 49<br> 18x + 9<br> 15x - 10
Vera_Pavlovna [14]

<em><u>Factorization is:</u></em>

5x+40=5(x+8)\\\\7x-49=7(x-7)\\\\18x+9=9(2x+1)\\\\15x-10=5(3x-2)

<h3><u>Solution:</u></h3>

Given that we have to factor the given expressions

<h3><u>First expression:</u></h3>

5x + 40

We have to take the greatest common factor out

When we find all the factors of two or more numbers, and some factors are the same then the largest of those common factors is the Greatest Common Factor

Take G.C.F of 5 and 40

The factors of 5 are: 1, 5

The factors of 40 are: 1, 2, 4, 5, 8, 10, 20, 40

Then the greatest common factor is 5

Factor out 5 from given expression

5x + 40 = 5(x+8)

<h3><u>Second expression:</u></h3>

7x - 49

Similarly, take G.C.F of 7 and 49

The factors of 7 are: 1, 7

The factors of 49 are: 1, 7, 49

Then the greatest common factor is 7

Factor out 7 from given expression

7x - 49 = 7(x-7)

<h3><u>Third expression:</u></h3>

18x + 9

Similarly, take G.C.F of 18 and 9

The factors of 9 are: 1, 3, 9

The factors of 18 are: 1, 2, 3, 6, 9, 18

Then the greatest common factor is 9

Factor out 9 from given expression

18x + 9 = 9(2x+1)

<h3><u>Fourth expression:</u></h3>

15x - 10

Similarly, take G.C.F of 15 and 10

The factors of 10 are: 1, 2, 5, 10

The factors of 15 are: 1, 3, 5, 15

Then the greatest common factor is 5

Factor out 5 from given expression

15x-10 = 5(3x-2)

Thus factorization is found

3 0
4 years ago
(tanx+cotx) squared is the same as
snow_lady [41]
It is same as <span>sec^2 x + csc^2 x </span>
3 0
3 years ago
Cindy worked 4 hours each day for 12 days. She earned a total of $240. How much did Cindy earn per hour?
vekshin1
The answer is $5 per hour
3 0
3 years ago
Read 2 more answers
A 15-day supply of vitamins costs $1.41, what is the price in cents per day
Free_Kalibri [48]
1.41/100 = 0.0141 * 15 = 0.21

$0.21
6 0
3 years ago
For each of the -3.3 trials, and in the same sequence in which you entered the freezing points, enter your calculated values for
dedylja [7]

Answer:

The morality of the solution is calculated as 0.859 m. We are required to determine the freezing point depression constant of pure water. The freezing point depression of the solution is given as

T_{f}  = T_{p}  -T_{s} = K_{f} * (morality of solution)

T_{p} and T_{s} are the freezing points of the pure solvent (water, 0°C) andK_{f} = freezing point depression constant of water. Therefore,

T_{f}  = K_{f} *(0.859 m)

=====> (0°C) – (3.00°C) = K_{f}  *(0.859 m)

=====> -3.00°C = K_{f}  *(0.859 m)

Ignore the negative sign (since K_{f} is positive) and get

K_{f} = (3.00°C) / (0.859 m) = 3.492°C/m

The freezing point depression constant of the solvent is 3.5°C kg/mole  

3.5 K.kg/mole (temperature differences are the same in Celsius and Kelvin scales).

3 0
3 years ago
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