The required probability of the coin landing tails up at least two times is 15/16.
Given that,
A fair coin is flipped seven times. what is the probability of the coin landing tails up at least two times is to be determined.
<h3>What is probability?</h3>
Probability can be defined as the ratio of favorable outcomes to the total number of events.
Here,
In the given question,
let's approach inverse operation,
The probability of all tails = 1 / 2^7 because there is only one way to flip these coins and get no heads.
The probability of getting 1 head = 7 /2^7
Adding both the probability = 8 / 2^7
Probability of the coin landing tails up at least two times = 1 - 8/2^7
= 1 - 8 / 128
= 120 / 128
= 15 / 16
Thus, the required probability of the coin landing tails up at least two times is 15/16.
Learn more about probability here:
brainly.com/question/14290572
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Negative times negative = positive.
=0.63−(−9.85)
=0.63+9.85
=10.48
D) is the answer.
Answer: 871.72 + (0.3926........x 42)
Step-by-step explanation: 23.56 x 37= 871.72
23.56/60= 0.3926................... x 42
Answer:
x≥3
Step-by-step explanation:
Treat the ≥ symbol like it is an equals sign. First, subtract 14x from each side to get 6x+12≥30. Then, Subtract 12 from each side to get 6x≥18. I will let you solve the rest :)
In a scientific notation, it would be: 1.5 × 10⁻⁸
In short, Your Answer would be 1.5 × 10⁻⁸
Hope this helps!
