Answer:
d.0.48
Explanation:
When a population is in Hardy Weinberg equilibrium the <u>genotypic </u>frequencies are:
freq (AA) = p²
freq (Aa) = 2pq
freq (aa) = q²
<em>p</em> is the frequency of the dominant <em>A</em> allele and <em>q</em> is the frequency of the recessive <em>a</em> allele.
In this population of 100 individuals, 84 martians have the dominant phenotype and 16 have the recessive phenotype.
Therefore:
q²=16/100
q² = 0.16
q=√0.16
q = 0.4
And p+q=1, so:
p = 1 - q
p = 1-0.4
p = 0.6
The frequency of heterozygotes is:
freq (Aa) = 2pq = 2 × 0.4 × 0.6
freq (Aa) = 0.48
Disease, competition, and predation.
Answer:
Regulating
Explanation:
According to Millennium Ecosystem Assessment, there are four major categories of ecosystem services. These services include:
1. Provisioning
2. Regulating
3. Supporting
4. Cultural
The Regulating category is the category that consists of Air and water quality - Purification, climate, erosion, disease transmission, and pest proliferation - Biological control, and pollination.
The ecosystem services are services or functions rendered by the natural environment that ensure the environment is sustainable and healthy for human use.
Answer:
cell grows, DNA replicates, cell prepares for mitosis, cell divides
