Find numbers that multiply to 28 and add them to see if they add to 8
28=
1 and 28=29 not 8
2 and 14=16 not 8
4 and 7=11 not 8
that's it'
no 2 numbers
we must use quadratic formula
x+y=8
xy=28
x+y=8
subtract x fromb oths ides
y=8-x
subsitute
x(8-x)=28
distribute
8x-x^2=28
add x^2 to both sides
8x=28+x^2
subtract 8x
x^2-8x+28=0
if you have
ax^2+bx+c=0 then x=
so if we have
1x^2-8+28=0 then
a=1
b=-8
c=28
x=
x=
x=
x=
x=
there are no real numbers that satisfy this
Answer:
16
Step-by-step explanation:
Answer:
There were 12 cranes in class yesterday. For all the cranes, there were a total of 290 centimeters.
Step-by-step explanation:
41-29=12.
29*10=290
Answer:
2 is the correct option.
Step-by-step explanation:
We have the equation 
.
We will plot the graphs of the function 
and 
.
Then, the intersection points of both the graph will be the solution of the equation .
From the graphs, we see that,
The intersection points of the graphs are (0,1) and (2.337,10.347).
The solution of the equation is the value of 'x' co-ordinate where they intersect.
So, we get, x = 2 is the correct option.
Answer:
377 meals
Step-by-step explanation:
If you choose to have all three courses, then there are 6 choices for the first course, 8 for the second, and 5 for the last, making a total of 6*8*5=240 different possible meals.
If you choose two courses, then there are 3 options. You can pick appetizer and main meal, which would give you 6*8=48 possibilities. You can pick main meal and dessert, which would give you 8*5=40 possibilities. Finally you can pick appetizer and desert, which would give you 6*5=30 possibilities. In total these are 118 different possible meals with two courses.
Finally, you could choose 1 course, which would give you 6+8+5=19 different meals.
In total, this is 240+118+19=377 meals
