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3 years ago

5

Mr. Green cuts his lawn every 8 days, while Mrs. Grasse cuts her lawn every 10 days. Suppose they both cut their lawns today. Wh

at is the least number of days that will pass before both Mr. Green and Mrs. Grasse cut their lawns on the same day again? *

1 answer:

stich3 [128]3 years ago

6 0

It will be in the next 40 days.

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Luda [366]

7b/12=4.2
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Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

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4 years ago

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ivolga24 [154]

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3 years ago

A room has a rectangular floor that is 15 feet by 21 feet. What is the area of the floor in square yards ?

Soloha48 [4]

Answer:

Hey There!

Let's solve...

Here it is a rectangular floor with length =21 cm and width =15cm

So

$area = l \times w \\ = 21 \times 15 \\ = 315 {ft}^{2} \\ \\$

So now We need to convert it to yards square

$315ft^{2} \times \frac{ {1yd}^{2} }{ {9ft}^{2} } \\ \\ = \cancel{315ft^{2}} \: ^{35} \times \frac{ {1yd}^{2} }{ \cancel{9 {ft}^{2} }} \\ \\ = 35 {yd}^{2}$

So how this 9 ft^2 came??

Let's know

$ft \to \: yards \\ \\ 3ft = 1yd \\ \\ {3ft}^{2} = {1yd}^{2} \\ \\ \boxed{ {9ft}^{2} = {1yd}^{2}}$

<h2>I hope it is helpful to you...</h2><h3>Cheers!_______</h3>

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