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3 years ago

What times 44 equals 2020

Mathematics

2 answers:

prohojiy [21]3 years ago

4 0

Answer:

its not a whole number

2020 divided by 44 in decimal = 45.90

2020 divided by 44 in fraction = 2020/44

2020 divided by 44 in percentage = 4590.90909091%

NARA [144]3 years ago

4 0

1 times 2020 equals 2020

2 times 1010 equals 2020

4 times 505 equals 2020

5 times 404 equals 2020

10 times 202 equals 2020

20 times 101 equals 2020

101 times 20 equals 2020

202 times 10 equals 2020

404 times 5 equals 2020

505 times 4 equals 2020

1010 times 2 equals 2020

2020 times 1 equals 2020

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I need help with this question on my geometry homework

Margarita [4]

Answer:

x = 250°

Step-by-step explanation:

Inscribed angle = ½(intercepted arc measure) (inscribed angles theorem)

x is intercepted arc measure

125° is the inscribed angle

Therefore:

125° = ½(x)

Multiply both sides by 2

2*125° = x

250 = x

x = 250°

7 0

3 years ago

17. Evaluate a. 6! b. 8P5 c. 12C4

Andreyy89

The factorial ! just means we multiply by every natural number less that the value so
6! =6×5×4×3×2×1= 720

for permutations we use the formula n!/(n-r)!
so we have 8!/(8-5)!=8!/3!=8×7×6×5×4

for combinations s we have n!/(n-r)!r!
so we have 12!/(12-4)!4!=12!/8!4!=12×11×10×9/4×3×2=11×10×9/2=99×5

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3 years ago

What are some methods to finding the distance between A and B

Wittaler [7]

Are a and b two points on a line
If they are you can use the distance formula

6 0

3 years ago

Please help and hurry!

artcher [175]

Answer: 3 option correct

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3 years ago

What’s the domain and range of:<br> log(√(2x-1) + 3 )<br> Please explain how you got it too!!

Radda [10]

Two main facts are needed here:

1. The logarithm $\log x$ , regardless of the base of the logarithm, exists for $x>0$ .

2. The square root $\sqrt x$ exists for $x\ge0$ .

(in both cases we're assuming real-valued functions only)

By (2) we know that $\sqrt{2x-1}$ exists if $2x-1\ge0$ , or $x\ge\dfrac12$ .

By (1), we know that $\log(\sqrt{2x-1}+3)$ exists if $\sqrt{2x-1}+3>0$ , or $\sqrt{2x-1}>-3$ . But as long as the square root exists, it will always be positive, so this condition will always be met.

Ultimately, then, we only require $x\ge\dfrac12$ , so the function has domain $\left[\dfrac12,\infty)$ .

To determine the range, we need to know that, in their respective domains, $\sqrt x$ and $\log x$ increase monotonically without bound. We also know that $x=\dfrac12$ at minimum, at which point the square root term vanishes, so the least value the function takes on is $\log3$ . Then its range would be $[\log3,\infty)$ .

3 0

3 years ago