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3 years ago

Determine the value of X

Mathematics

1 answer:

mr_godi [17]3 years ago

6 0

Answer:

x=17

Step-by-step explanation:

There are two congruent angles so we can double the given values and set that equal to 360. After setting that equal to 360 you find that x is equal to 17, then you plug that into the original equations and get your angles

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If f(x)=-4x+1 what is f(-x/2)

guapka [62]

Answer:

f( $\frac{-x}{2}$ )=2x+1

Step-by-step explanation:

given f(x)=-4x+1................(1)

x= $\frac{-x}{2}$ put in equ (1)

f(x)=-4x+1

f( $\frac{-x}{2}$ ) =-4( $\frac{-x}{2}$ )+1

f( $\frac{-x}{2}$ )=2x+1 answer

5 0

3 years ago

The race begins at the rate of 1.5 meters per second. what distance, d, is covered after t second

Nitella [24]

1 second = 1.5 meters
t second = 1.5t meters

---------------------------
Answer: d = 1.5t
---------------------------

4 0

3 years ago

98 Points! MATH SOLVING SYSTEMS OF LINEAR EQUATIONS

photoshop1234 [79]

Answer:

40 Tickets

80 Tickets

Step-by-step explanation:

To find how many tickets it will take to break even, we use the formula:

$Break Even In Units = \dfrac{FixedCost}{SalesPricePerUnit-VariableCost}$

Our variables are:

Fixed Cost = $200

Sales Price = $10

Variable Cost = $5

Let's plug in our values into the formula.

$Break Even In Units = \dfrac{200}{10-5}$

$Break Even In Units = \dfrac{200}{5}$

$Break Even In Units = 40$

So the class needs to sell a total of 40 Tickets to break even.

Since we know that it takes 40 tickets to break even a $200 Fixed cost. To make a profit of $200, we simply multiply the number of tickets sold by 2.

Number of tickets for $200 profit = 40 x 2

Number of tickets for $200 profit = 80 Tickets.

So the class needs to sell 80 Tickets to make a $200 Profit.

5 0

3 years ago

What is the answrs for number 9, with proof

Nuetrik [128]

Answer:

1. 30

2. 34

Step-by-step explanation:

2(4(3) + 3)

2(12 + 3)

2(15)

= 30

12(3) - 2

36 - 2

= 34

hope this helps :)

8 0

2 years ago

An airplane climbs 100 feet during the first second after takeoff. In each succeeding second it climbs 100 feet more than it cli

tigry1 [53]

Answer:

15 seconds.

Step-by-step explanation:

∵ The distance covered by plane in first second = 100 ft,

Also, in each succeeding second it climbs 100 feet more than it climbed during the previous second,

So, distance covered in second second = 200,

In third second = 300,

In fourth second = 400,

............, so on....

Thus, the total distance covered by plane in n seconds = 100 + 200 + 300 +400......... upto n seconds

$=\frac{n}{2}(2\times 100 + (n-1)100)$ ( Sum of AP )

$=\frac{n}{2}(200+100n-100)$

$=\frac{n}{2}(100+100n)$

$=50n+50n^2$

Suppose the distance covered in n seconds is 12,000 feet,

$\implies 50n+50n^2=12000$

$n+n^2=240$

$n^2+n-240=0$

$n^2+16n-15n-240=0$

$n(n+16)-15(n+16)=0$

$(n-15)(n+16)=0$

$\implies n=15\text{ or }n=-16$

∵ n can not be negative,

Hence, after 15 seconds the plane will reach an altitude of 12,000 feet above its takeoff height.

6 0

3 years ago

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