Question

Find the area of an equilateral triangle with a side of 6 inches

Answer 1

Answer:

Step-by-step explanation:

the answer would be 7.5

Answer 2

Answer:

15.59 inches²

Step-by-step explanation:

Area of a triangle = $\frac{1}{2}$ (base) × (height)

Base of the triangle = 6 inches = BC

so BD = CD = 3 inches

Now height h = AD = $\sqrt{6^{2}- 3^{2} }$ [ By Pythagoras theorem ]

h = $\sqrt{36-9}$

= $\sqrt{27}$

= $\sqrt[3]{3}$

Now area of equilateral triangle ABC

= $\frac{1}{2}$  (6) ( $\sqrt[3]{3}$)

= 3 ×  ($\sqrt[3]{3}$)

=  $\sqrt[9]{3}$ inches²

≈ 15.59 inches²