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2 years ago

find a polynomial equation of the lowest degree with rational coefficients whose one root is (cbrt 2 + 3*cbrt 4)

Mathematics

1 answer:

sweet-ann [11.9K]2 years ago

3 0

Answer:

poly Gon have $\huge\color{blue}{ \rule{1pt}{999999pt}}$ $\huge\color{blue}{ \rule{1pt}{999999pt}}$ $\huge\color{blue}{ \rule{1pt}{999999pt}}$ $\huge\color{blue}{ \rule{1pt}{999999pt}}$ $\huge\color{blue}{ \rule{1pt}{999999pt}}$ $\huge\color{blue}{ \rule{1pt}{999999pt}}$ $\huge\color{blue}{ \rule{1pt}{999999pt}}$ $\huge\color{blue}{ \rule{1pt}{999999pt}}$

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Nadia is a stockbroker. She earns 12% commission each week. Last week, she sold $5400 worth of stocks. How much did she make las

Inga [223]

Answer:

a). Nadia made a total of $825 last week in commission sales

b). The total amount Nadia in commission in 2011=$42,900

Step-by-step explanation:

Step 1

Express the amount in commission she earns from her sales as follows;

C=S×r

where;

C=commission earned

S=total value of stock sales

r=commission rate

In our case;

C=unknown

S=$7,500

r=11%=11/100=0.11

replacing;

C=11% of 7,500

C=(11/100)×7,500

C=0.11×7,500=825

Nadia made a total of $825 last week in commission sales

b). To express the total amount she made in 2011, we derive the formula below;

Total amount (2011)=Average weekly commission×number of weeks in 2011

where;

Average weekly commission=$825

number of weeks in 2011=52

replacing;

Total amount (2011)=(825×52)=42,900

The total amount Nadia in commission in 2011=$42,900

6 0

3 years ago

Use f’( x ) = lim With h ---> 0 [f( x + h ) - f ( x )]/h to find the derivative at x for the given function. 5-x²

beks73 [17]

<h2>Answer:</h2>

The derivative of the function f(x) is:

$f'(x)=-2x$

<h2>Step-by-step explanation:</h2>

We are given a function f(x) as:

$f(x)=5-x^2$

We have:

$f(x+h)=5-(x+h)^2\\\\i.e.\\\\f(x+h)=5-(x^2+h^2+2xh)$

( Since,

$(a+b)^2=a^2+b^2+2ab$ )

Hence, we get:

$f(x+h)=5-x^2-h^2-2xh$

Also, by using the definition of f'(x) i.e.

$f'(x)= \lim_{h \to 0} \dfrac{f(x+h)-f(x)}{h}$

Hence, on putting the value in the formula:

$f'(x)= \lim_{h \to 0} \dfrac{5-x^2-h^2-2xh-(5-x^2)}{h}\\\\\\f'(x)=\lim_{h \to 0} \dfrac{5-x^2-h^2-2xh-5+x^2}{h}\\\\i.e.\\\\f'(x)=\lim_{h \to 0} \dfrac{-h^2-2xh}{h}\\\\f'(x)=\lim_{h \to 0} \dfrac{-h^2}{h}+\dfrac{-2xh}{h}\\\\f'(x)=\lim_{h \to 0} -h-2x\\\\i.e.\ on\ putting\ the\ limit\ we\ obtain:\\\\f'(x)=-2x$

Hence, the derivative of the function f(x) is:

$f'(x)=-2x$

3 0

3 years ago

Read 2 more answers

I need help I’m on my last questionnn

LenKa [72]

Answer:

7.3 in

Step-by-step explanation:

Area of triangle = (1/2) *b*h

27 = (1/2) * x^2

54 = x^2

square root (54) = x

x=> 7.3484....

Rounding off to 1 decimal place, you get 7.3 in.

8 0

2 years ago

Read 2 more answers

If f(x)=3^x+10x and g(x)=4x-2, find (f+g)(x)

Vikentia [17]

Hi there!

First we need to remember the following.
$(f + g)(x) = f(x) + g(x)$

Now substitute both of the formulas.
$(f + g)(x) = ({3}^{x} + 10x)+ (4x - 2)$

Work out the parenthesis.
$(f + g)(x) = {3}^{x} + 10x + 4x - 2$

And finally collect terms.
$(f + g)(x) = {3}^{x} + 14x - 2$

~ Hope this helps you!

3 0

3 years ago

Read 2 more answers

(b) Paul uses the function y = 8x + 40 to model the situation. What score does the model predict for 3 h of homework? WILL MARK

Bess [88]

Assuming that $x$ is the amount of hours spent doing homework:

Plug in $3$ for $x$

$y = 8(3)+40$ , $y=64$

That means that since a $y$ value is the test score (because that's what the y-axis is labeled), your predicted test score is a 64.

8 0

3 years ago