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german
2 years ago
12

find a polynomial equation of the lowest degree with rational coefficients whose one root is (cbrt 2 + 3*cbrt 4)

Mathematics
1 answer:
sweet-ann [11.9K]2 years ago
3 0

Answer:

poly Gon have \huge\color{blue}{ \rule{1pt}{999999pt}}\huge\color{blue}{ \rule{1pt}{999999pt}}\huge\color{blue}{ \rule{1pt}{999999pt}}\huge\color{blue}{ \rule{1pt}{999999pt}}\huge\color{blue}{ \rule{1pt}{999999pt}}\huge\color{blue}{ \rule{1pt}{999999pt}}\huge\color{blue}{ \rule{1pt}{999999pt}}\huge\color{blue}{ \rule{1pt}{999999pt}}

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Find the sum of the first 150 positive even integers.
Gnoma [55]

Answer:

22650

Step-by-step explanation:

3 0
2 years ago
AB = 44 + 3xBC = 33 + yCD = 64 − xAD = 48 − 2yQuadrilateral ABCD is a parallelogram if both pairs of opposite sides are congruen
Otrada [13]

The lengths (in centimeters) of the opposite side pairs are 59 cm , 38 cm. Option C) is the correct answer.

<u>Step-by-step explanation</u>:

<u>step 1</u> :

Given that,

Quadrilateral ABCD is a parallelogram if both pairs of opposite sides are congruent.

<u>step 2</u> :

The opposite sides are AB and CD respectively.

The another opposite sides are BC and AD respectively.

<u>step 3</u> :

If both pairs of opposite sides are congruent, then

AB = CD

44+3x = 64-x

3x+x = 64-44

4x = 20

x = 5

<u>step 4</u> :

BC = AD

33+y = 48-2y

y+2y = 48-33

3y = 15

y = 5

<u>step 5</u> :

Subsitute x=5 and y=5 in any of the given sides,

CD = 64-x = 64-5 = 59

∴ CD = 59 cm

BC = 33+y = 33+5 = 38

∴ BC = 38 cm

The lengths of the opposite side pairs are 59 cm , 38 cm.

3 0
3 years ago
2x+x(x+6)<br> Solve to the lowest equation/number
Ghella [55]

Answer:

x^2 +8x

Step-by-step explanation:

2x+x(x+6)

Distribute

2x + x^2 +6x

Combine like terms

x^2 +8x

7 0
3 years ago
Read 2 more answers
What are the first nine multiples of 5, and 3?
andrezito [222]

First 9 multiples of 5:

\begin{gathered} 5\cdot1=5 \\ 5\cdot2=10 \\ 5\cdot3=15 \\ 5\cdot4=20 \\ 5\cdot5=25 \\ 5\cdot6=30 \\ 5\cdot7=35 \\ 5\cdot8=40 \\ 5\cdot9=45 \end{gathered}

First 9 multiples of 3:

\begin{gathered} 3\cdot1=3 \\ 3\cdot2=6 \\ 3\cdot3=9 \\ 3\cdot4=12 \\ 3\cdot5=15 \\ 3\cdot6=18 \\ 3\cdot7=21 \\ 3\cdot8=24 \\ 3\cdot9=27 \end{gathered}

3 0
1 year ago
The base BC of an equilateral triangle ABC lies on y-axis. The coordinates of points C are (0, -3). The origin is the mid –point
Kobotan [32]

Answer

Point b is (0,0) Point a is (3,-2) Im not doing the second part

Step-by-step explanation:

6 0
3 years ago
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