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Vitek1552 [10]
3 years ago
14

What is the solution to 4log4(x+8)=4^2

Mathematics
2 answers:
kotegsom [21]3 years ago
6 0
4log₄(x+8)=4²
⇒ log₄(x+8) = 4²:4
⇒ log₄(x+8)= 4
⇒ x+8 = 4⁴
⇒ x+8 = 256
⇒ x = 256 - 8
⇒ x = 248


Verification : 4log₄(248+8) = 4log₄256 = 4*4 = 4² = 16 - TRUE

iVinArrow [24]3 years ago
3 0

Answer:

The answer is 8.

Step-by-step explanation:

Just took the quiz and that it correct.

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Solve 4x- c = k for x. <br>A. x = k-c/4<br>B. x = 4(k-c)<br>C. x- k+c/4<br>D. x = 4 (k+c)​
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A

Step-by-step explanation:

You would first add c to the side that k is on and then divide k+c by 4 because it is 4x which means they are being multiplied together so you have to divide to get them apart.

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Reparametrize the curve with respect to arc length measured from the point where t = 0 in the direction of increasing t. (Enter
jolli1 [7]

Answer:

the answer is incomplete, below is the complete question

"Reparametrize the curve with respect to arc length measured from the point where t = 0 in the direction of increasing t. (Enter your answer in terms of s.) r(t) = 3ti + (1 - 4t)j + (1 + 2t)k r(t(s)) ="

answer

r(t(s)) = \frac{3s}{\sqrt{29} } i + (1 -\frac{4s}{\sqrt{29} }t)j + (1 + \frac{2s}{\sqrt{29} })k

Step-by-step explanation:

The step by step procedure is to first determine the differentiate the given vector function

r(t) = 3ti + (1 - 4t)j + (1 + 2t)k

\frac{d(r(t) = 3ti + (1 - 4t)j + (1 + 2t)k)}{dt} \\r'(t)=3i-4j+2k\\

since s(t) is the arc length for r(t), which is define as

s(t)=\int\limits^t_0 {||r'(t)||} \, dt

if we substitute the value of r'(t) we arrive at

s(t)=\int\limits^t_0 {||r'(t)||} \, dt\\s(t)=\int\limits^t_0 {\sqrt{3^{2} +4^{2}+2^{2}} \, dt\\s(t)=\int\limits^t_ 0{\sqrt{29} } \, dx\\

s(t)=\int\limits^t_ 0{\sqrt{29} } \, dx\\\\s(t)=\sqrt{29} t\\hence \\t(s)=\frac{s}{\sqrt{29} }

substituting the value of t in to the given vector equation we have

r(t(s)) = \frac{3s}{\sqrt{29} } i + (1 -\frac{4s}{\sqrt{29} }t)j + (1 + \frac{2s}{\sqrt{29} })k

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Answer:

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Step-by-step explanation:

If volume of the prism = 15

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