The volume of the sphere with a radius of 9.1ft is 3256.55cubic feet.
We have given that, the radius of the sphere is 9.1ft.
We have to determine the volume of the sphere
<h3>What is the formula for the volume of the sphere?</h3>
The volume of the sphere is given by
![V=\frac{4}{3}\pi r^3](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3)
r is the radius of the sphere
V- is the volume of the sphere
So use the given value in the formula so that,
![V=\frac{4}{3}\pi (9.1)^3](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20%289.1%29%5E3)
![V=3156.55082 ft^3](https://tex.z-dn.net/?f=V%3D3156.55082%20ft%5E3)
Therefore the volume of the sphere with a radius of 9.1ft is 3256.55cubic feet.
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Answer:
c. should be the right answer if I'm correct
0 = (x – 3)(x – 3)
x - 3 = 0
x = 3
Solution is x = 3 (one real solution)
Answer
0 = (x – 3)(x – 3)
Answer:
x = -3 and x = 1/2
Step-by-step explanation:
To find the solutions to
2x² + 5x - 3 = 0
we can use the quadratic formula, as follows:
![x = \frac{-b \pm \sqrt{b^2- 4(a)(c)}}{2(a)}](https://tex.z-dn.net/?f=%20x%20%3D%20%5Cfrac%7B-b%20%5Cpm%20%5Csqrt%7Bb%5E2-%204%28a%29%28c%29%7D%7D%7B2%28a%29%7D%20)
![x = \frac{-5 \pm \sqrt{5^2- 4(2)(-3)}}{2(2)}](https://tex.z-dn.net/?f=%20x%20%3D%20%5Cfrac%7B-5%20%5Cpm%20%5Csqrt%7B5%5E2-%204%282%29%28-3%29%7D%7D%7B2%282%29%7D%20)
![x = \frac{-5 \pm 7}{4}](https://tex.z-dn.net/?f=%20x%20%3D%20%5Cfrac%7B-5%20%5Cpm%207%7D%7B4%7D%20)
![x_1 = \frac{-5 + 7}{4}](https://tex.z-dn.net/?f=%20x_1%20%3D%20%5Cfrac%7B-5%20%2B%207%7D%7B4%7D%20)
![x_1 = 0.5](https://tex.z-dn.net/?f=%20x_1%20%3D%200.5%20)
![x_2 = \frac{-5 - 7}{4}](https://tex.z-dn.net/?f=%20x_2%20%3D%20%5Cfrac%7B-5%20-%207%7D%7B4%7D%20)
![x_2 = -3](https://tex.z-dn.net/?f=%20x_2%20%3D%20-3%20)
Answer:
31°
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