Question

Will give brainliest to best answer Calculate

Answer 1

Answer:

Oh! that expression is equal to 4

Step-by-step explanation:

$\sqrt{2\sqrt{7} -\sqrt{12} } \cdot \sqrt{2\sqrt{7} +\sqrt{12} }$

First, rewrite $\sqrt{12} =\sqrt{2 \cdot 2 \cdot 3}=2\sqrt{3}$

$\sqrt{2\sqrt{7} -2\sqrt{3} } \cdot \sqrt{2\sqrt{7} +2\sqrt{3} }$

$\sqrt{2\sqrt{7} -2\sqrt{3} } \cdot \sqrt{2\sqrt{7} +2\sqrt{3} }$

Now we got a difference of two squares, therefore,

$(2\sqrt{7} -2\sqrt{3})(2\sqrt{7} +2\sqrt{3})=(2\sqrt{7} )^2-(2\sqrt{3})^2=$

$= (4 \cdot 7)-(4 \cdot3)=28-12=16$

$\sqrt{2\sqrt{7} -2\sqrt{3} } \cdot \sqrt{2\sqrt{7} +2\sqrt{3} }=\sqrt{16}$

$\sqrt{16} = 4$

Answer 2

Answer:

I think 4.932651

Step-by-step explanation: