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nikklg [1K]
3 years ago
10

Is 1/8 greater than 2/10

Mathematics
2 answers:
emmasim [6.3K]3 years ago
3 0

No, 1/8 is smaller because 2/10 is equivalent to 1/5 and 1/5 is larger than 1/8.
mr Goodwill [35]3 years ago
3 0
No, 2/10 is = to 1/5, which is greater than 1/8
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I need help with this please
Lelechka [254]

There are 36 possible combinations that can occur when 2 dice are rolled. For the sake of this question, we'll count instances where dice 1 = 3/dice 2 = 2 and dice 1 = 2/dice 2 = 3.

Now, let's think about all of the possible ways a total of 5 could be rolled.

1 + 4

2 + 3

3 + 2

4 + 1

That's 4 possibilities to roll a total of 5 out of 36 possible outcomes.

4 / 36 = ? / 180

---Now, we need to use a proportion in order to figure out the possibilities out of 180.

36x = 720

x = 20

If you rolled a pair of fair dice 180 times, you would expect to roll a total of 5, 20 times.

Hope this helps!

4 0
2 years ago
An 11-ft ladder leans against the side of a house. The bottom of the ladder is 9-ft from the side of the house. How high is the
bulgar [2K]

Answer:

6.3 ft.

Step-by-step explanation:

This requires the pythagorean theorem: a^2+b^2=c^2 where "a" and "b" are legs and c is the hypotenuse(longest side of the triangle which is opposite to the 90 degree angle.) If we fill the equation where c is the ladder length(11) and "a" is the distance from the house(), and "b" is the height, 9^2+b^2=11^2 or 81+b^2=121. This is equivalent to b^2=40. b=6.3 when rounded to the nearest tenth.

4 0
3 years ago
Answer this please. Thank you! Worth 10 points as well.
nlexa [21]
The probability that the next 4 winners will all be 7th grade students is 3/4
3 0
3 years ago
Iodine-125 has a daily decay rate of about 1%. How many milligrams of a 500 mg sample will remain after 300 days? Round the answ
Amanda [17]
So.. in this case, the starting amount is the 500mg sample... and the rate of decay, negative rate, is 1%, and at the time, the elapsed days is 0, to t = 0, P = 400

\bf \qquad \textit{Amount for Exponential change}\\\\
A=P(1\pm r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{starting amount}\to &500\\
r=rate\to 1\%\to \frac{1}{100}\to &0.01\\
t=\textit{elapsed period}\to &300\\
\end{cases}
\\\\\\
A=500(1-0.01)^{300}
7 0
3 years ago
Read 2 more answers
Factor the expression 15x^2-16xy+4y^2
Zepler [3.9K]

(5x-2y)(3x-2y)


Dont give me anything give it to the other lad down there


6 0
3 years ago
Read 2 more answers
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