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4 years ago

What is the describes the number 5? Write prime composite neither prime nor composite or both prime and composite

2 answers:

7 0

Prime. Whether a number is prime or composite depends on whether or not you can "break it down" by multiplication. Primes are the building blocks of the counting numbers in the sense that any number can be written in the form of one or more primes multiplied together. We call numbers created with two or more primes in this way <em>composite</em>, and we leave the number 1 out of the discussion as a number that's neither prime nor composite.

5 only has 1 building block: 5. It <em>is </em>a building block.

TiliK225 [7]4 years ago

4 0

prime is your answer

have a nice day stranger

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A circle has a radius of 9 inches. The Radius is multiplied by 2/3 to form a second circle. How is the ratio of the areas relate

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$\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81}{36} = (\frac{r_{1} }{r_{2}}) ^{2}$

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Step-by-step explanation:

Radius of first circle $(r_{1})$ = 9 inches

Area of first circle = $\pi r_{1} ^{2}$

Area of first circle = 9 × 9 × π = 81 π

Now, since the radius is multiplied by 2/3 for from a new circle.

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Area of second circle = $\pi r_{2} ^{2}$

Area of second circle = 6 × 6 × π = 36 π

Now,

$\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81\pi }{36\pi }$

$\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81}{36} = (\frac{9}{6}) ^{2} = (\frac{r_{1} }{r_{2}}) ^{2}$

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3 years ago

The perimeter of a playing field for a certain sport is 214 ft. The field is a rectangle, and the length is 41 ft longer than th

Shtirlitz [24]

Answer:

width: 33 ft

length: 74 ft

Step-by-step explanation:

The perimeter of a rectangle is calculated by adding all of the sides together which includes two lengths and two widths. Since the formula for the length is given (l = 41ft + w) and the perimeter is given, then we can simply use the perimeter formula and substitute the value of length with its formula which would only leave us with one variable in the equation w. Now we must solve for w.

l + l + w + w = 214

(41 + w) + (41 +w) + w + w = 214 ... combine like terms

82 + 4w = 214 ... subtract 82 from both sides

4w = 132 ... divide both sides by 4

w = 33 ft

Finally, we can see that the value of the width is 33 ft . Now we plug this value into the formula for length to calculate its value.

l = 41 + w

l = 41 + 33

l = 74 ft

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