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Tresset [83]
3 years ago
15

there are 30 students in mr. Holland music class. If 30% of the students play in the school band, how many students in the class

play in the school band?
Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
3 0
9 students 30% ends up being .3%, multiply .3% by 30 students which equals 9.
ra1l [238]3 years ago
3 0
The number of students playing in the school band is:
30 students*(30%)
= 30 students*30/100
= 9 students
Hope this would help :))
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Factors of 30 that adds up to 17
anyanavicka [17]
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Consider <img src="https://tex.z-dn.net/?f=%24%5Ctriangle%20ABC%24%20such%20that%20%24BC%20%3D%203AC%24%20and%20%24%5Cangle%20A%
Gemiola [76]

The answer to the question is,

12 sin(∠B) = 2,           12 sin(∠C) = √3+√35

Sin rule is,

sin(A)/BC = sin(B)/AC = sin(C)/AB

sin(B) = (sin(A)×AC)/BC

sin(C) =(sin(B)×AB)/AC

To solve this question we apply sin rule,

Now we take

12 sin(∠B) =12 (sin(∠A)×AC)/BC

12 sin(∠B) =12 (sin(π/6)×(x/3x))          where ∠A =π/6 and AC=x, BC =3x

12 sin(∠B) =12 ((1/2)×(1/3))

12 sin(∠B) =12/6 = 2

12 sin(∠B) = 2

now we find the value of 12 sin(∠C)

12 sin(∠C) = 12(sin B)×(AB/BC)

now put the value of 12 sin(∠B) = 2

12 sin(∠C) = 2×(AB/BC)

12 sin(∠C) = (2/AC)×[AC×(cos(π/6))+BC×(cos B)]

12 sin(∠C) = 2×[cos(π/6)+(BC/AC)×(cos B)]

cos (π/6) = √3/2 and BC/AC =3

then

12 sin(∠C) = 2×[(√3/2)+3×(cos B)]

cos B= √1-sin²B

12 sin(∠C) = 2×[(√3/2)+3×√(1-sin²B)]

12 sin(∠B) = 2

sin B = 1/6

12 sin(∠C) = 2×[(√3/2)+3×√(1-(1/6)²]

12 sin(∠C) = 2×[(√3/2)+3×√1-(1/36)]

12 sin(∠C) = 2×[(√3/2)+3×√(36-1)/36]

12 sin(∠C) = 2×[(√3/2)+3×√(35/36)]

12 sin(∠C) = 2×[(√3/2)+(3/6)×√35]

12 sin(∠C) = 2×[(√3/2)+(1/2)×√35]

12 sin(∠C) = 2×[(1/2)(√3+√35)]

12 sin(∠C) = √3+√35

Hence the answer is,

12 sin(∠B) = 2,         12 sin(∠C) = √3+√35

Learn more about triangles rules from:

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6 0
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The point P(x, y) lies on the terminal side of an angle mc014-1.jpg = –60° in standard position. What are the signs of the value
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When a point divide a line segment A (x1,y1) B (x2,y2) into a ration of a:b, the coordinates of that point is x1+[a/(a+b)](x2-x1), y1+[a/(a+b)](y2-y1)
so x=0+(2/3)(6-0)=4
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(4, 6&2/3) is the answer. 
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