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Leya [2.2K]
2 years ago
12

Use the Change of Base Formula to evaluate the expression. Then convert it to a logarithm in base 8. Round to the nearest thousa

ndth if necessary.
log4 8

0.667; log8 4.003

0.301; log8 1.870

1.5; log8 22.627

0.15; log8 1.366
Mathematics
1 answer:
Crazy boy [7]2 years ago
3 0

Answer

1.5; log8 22.627

Step-by-step explanation:

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Plz give correct answer! (might give brainliest) :)<br><br><br> thnx, have a nice day!
neonofarm [45]

Answer:

56

Step-by-step explanation:

(14-7)×(40-32)

(7)×(8)

56

5 0
3 years ago
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Pls answer now<br> i gave you brainlest
slava [35]

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5 0
2 years ago
PLEASE HELP ME!!!
Gennadij [26K]

Answer:

8 spoons and 9 forks

Step-by-step explanation:

2 F + 1.2S = 27.60

6 F + 5.5S = 98

solve system of equations

7 0
3 years ago
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F(x)=(5x+3)(x−2)(3x+7)(x+5) has zeros at x = -5, x = -7/3, x = 2
musickatia [10]

The sign of f on the interval -7/3 < x < -3/5 is always positive.

<h3>How to solve for the sign on the interval</h3>

We have the equation

(5x+3)(x−2)(3x+7)(x+5) > 0

Now when f(x) > 0

Then -7/3 < x < -3/5

This would tell us that the sign would become positive when it changes from the less than to greater than sign

<h3>Complete Question</h3>

f(x)=(5x+3)(x-2)(3x+7)(x+5) has zeros at x=-5, x=-7/3, x=-3/5, and x=2

What is the sign of f on the interval -7/3<x<-3/5?

answer choices

f is always positive on the interval

f is always negative on the interval

f is sometimes positive and sometimes negative on the interval

f is never positive or negative on the interval

Read more on polynomials here:

brainly.com/question/2833285

#SPJ1

5 0
2 years ago
Need help with this question
velikii [3]
All you have to do is plug in the given x values. your first equations would read:

f(-3) = 2^(-3)
f(-2) = 2^(-2)
f(-1) = 2^(-1)

these can be solved by moving decimal points or entering them into a calculator. regardless of the method, your answers are:

f(-3) = 0.002
f(-2) = 0.02
f(-1) = 0.2

so just repeat that process to fill in the rest of your table. to graph it, you'll use them as normal (x, y) points:

(-3, 0.002)
(-2, 0.02)
(-1, 0.2)

the graph might be a little difficult, working with such small values, but precision isn't totally important--0.002 will be super close to 0, 0.02 will be slightly further, 0.2 will be slightly further. the smaller values don't matter as much graphically and you'll recognize the graph of a growing exponential as you graph more of the table.
7 0
3 years ago
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