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nekit [7.7K]
3 years ago
12

Make an standard form equation based on this graph.

Mathematics
1 answer:
OLga [1]3 years ago
3 0

Answer:

y = -1/4x - 2

Step-by-step explanation:

Step 1: The y-intercept is on the y-axis line. The y-intercept in this graph is -2.

Step 2: To find the slope. The line is going downwards so that helps us know that the slope is going to be negative. You want to get the bottom point to the top. So move upwards 1 time and move 4 times to the left.

Step 3: Now just put everything together.

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O
jekas [21]

Answer:

b= -8

Step-by-step explanation:

we have: 3y +12 = 6x <=> y + 4 = 2x <=> y= 2x - 4

=> 2y=4x + b

<=> 2(2x-4) = 4x +b

<=> 4x - 8= 4x +b

<=> b = -8

6 0
3 years ago
Read 2 more answers
How many orders of magnitude bigger is 23,000 than 56?
Daniel [21]

Orders of Magnitude are in terms of scientific notation.

23,000 written in scientific notation is 2.3 x 10^4, it's magnitude is 4 ( the number 10 is raised to)

56 in scientific notation would be 5.6 x 10^1, its magnitude is 1.

4 - 1 = 3

2300 is 3 order of magnitudes larger.

The answer is 3.

4 0
3 years ago
NEED HELP PLS
AnnZ [28]

Answer:

First

Step-by-step explanation:

The first person in the line will always have an odd position, not an even one.  They will be the only one left.

6 0
3 years ago
A builder is finishing a new vet clinic and wants to install a drip edge along the roof. The edging he has decided to use comes
Nata [24]
69 rolls in total will be needed
3 0
3 years ago
The dwarves of the Grey Mountains wish to conduct a survey of their pick-axes in order to construct a 99% confidence interval ab
Dmitry_Shevchenko [17]

Answer:

The minimum sample size needed is 125.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

\pi = 0.25

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

What minimum sample size would be necessary in order ensure a margin of error of 10 percentage points (or less) if they use the prior estimate that 25 percent of the pick-axes are in need of repair?

This minimum sample size is n.

n is found when M = 0.1

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.1 = 2.575\sqrt{\frac{0.25*0.75}{n}}

0.1\sqrt{n} = 2.575{0.25*0.75}

\sqrt{n} = \frac{2.575{0.25*0.75}}{0.1}

(\sqrt{n})^{2} = (\frac{2.575{0.25*0.75}}{0.1})^{2}

n = 124.32

Rounding up

The minimum sample size needed is 125.

5 0
3 years ago
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