<h2>
The area of a triangle is =54 square units</h2><h2>
The perpendicular distance from B to AC is = 
</h2>
Step-by-step explanation:
Given a triangle ABC with vertices A(2,1),B(12,2) and C(12,8)
The area of a triangle is= ![\frac{1}{2} [x_1(y_2-y_3) +x_2 (y_3- y_1)+x_3(y_1-y_2)]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Bx_1%28y_2-y_3%29%20%2Bx_2%20%28y_3-%20y_1%29%2Bx_3%28y_1-y_2%29%5D)
=![|\frac{1}{2} [2(2-8+12(8-1)+12(1-2)]|](https://tex.z-dn.net/?f=%7C%5Cfrac%7B1%7D%7B2%7D%20%5B2%282-8%2B12%288-1%29%2B12%281-2%29%5D%7C)
=
= 54 square units
The length of AC = 
= 
=
units
Let the perpendicular distance from B to AC be = x
According To Problem
⇔
units
Therefore the perpendicular distance from B to AC is =
Estimation: about 6,000 (90x70=6300)
Answer (product): 6256
Answer:
5x+2y =-6 ........1
3x-2y = 22 ........2
Add both Equations
we get
8x = 16
Divide both sides by 8
x = 2
Substitute x = 2 into any of the equations
3(2) - 2y = 22
-2y = 22 - 6
- 2y = 18
Divide both sides by -2
y = - 9
x = 2 y = - 9
Hope this helps
Answer:
Step-by-step explanation:
Given is a function of x
When y=0 we get x=0 and infinity
Hence x intercept is 0 and one asymptote is x axis.
When x=0 , y =0
Maxima at x=1, and point of inflection is at x=2
Increasing upto x=1 and then decreases
Graph is enclosed
Answer:
x = 46°
Step-by-step explanation:
the opposite angles of a cyclic quadrilateral are supplementary, sum to 180° , then
x + 134° = 180° ( subtract 134° from both sides )
x = 46°
