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2 years ago

Help me with this please

Mathematics

1 answer:

ElenaW [278]2 years ago

5 0

The greatest common factor is 2z^3.

In order to find the greatest common factor, always start with the coefficient of the lowest term. Let's see what the factors of 14 are.

Factors of 10: 1, 2, 5, 10

Now we look to see which are also factors of the next highest number.

Factors of 14: 1, 2, 7, 14

Only 1 and 2 are similar factors. Since 2 is also a factor of 70, 2 in the coefficient of our greatest common factor.

Next we look for the term with the least number of z's. 14z^3 is the least number of z's. This means we can take out z^3. Giving us the final answer of 2z^3.

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Read 2 more answers

Consider the following hypothesis test.H0:μ1−μ2=0 Ha:μ1−μ2≠0The following results are for two independent samples taken from the

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a) $z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53$

b) $p_v =2*P(z$

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Step-by-step explanation:

Information given

$\bar X_{1}= 104$ represent the mean for 1

$\bar X_{2}= 106$ represent the mean for 2

$\sigma_{1}= 8.4$ represent the population standard deviation for 1

$\sigma_{2}= 7.6$ represent the population standard deviation for 2

$n_{1}=80$ sample size for the group 1

$n_{2}=70$ sample size for the group 2

z would represent the statistic

Hypothesis to test

We want to check if the two means for this case are equal or not, the system of hypothesis would be:

H0: $\mu_{1}=\mu_{2}$

H1: $\mu_{1} \neq \mu_{2}$

The statistic would be given by:

$z =\frac{\bar X_1-\bar X_2}{\sqrt{\frac{\sigma^2_1^2}{n_1} +\frac{\sigma^2_2^2}{n_2}}}=$ (1)

Part a

Replacing we got:

$z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53$

Part b

The p value would be given by this probability:

$p_v =2*P(z$

Part c

Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

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