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2 years ago

9. Solve the equation for x. 3x + y = 2 Z

Mathematics

1 answer:

frutty [35]2 years ago

6 0

Answer:

x= 2/3 -1/3y or x= -1/3y + 2/3

Step-by-step explanation:

3x + y= 2 (subtract the y to get 3x by itself)

3x= 2-y (divide both sides by 3 to get x by itself)

x= 2/3 - 1/3y

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I need help with this question please

madam [21]

Answer:go there and it will answer your question

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Step-by-step explanation:

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2 years ago

Before conducting some experiments, a scientist mixes 1/2 gram of Substance A with 3/4 grams of Substance B. If the scientist us

Tju [1.3M]

Answer: 10

<u>Step-by-step explanation:</u>

$(\frac{1}{2}+\frac{3}{4})$ ÷ $\frac{1}{8}$

= $(\frac{1}{2}(\frac{2}{2})+\frac{3}{4})$ ÷ $\frac{1}{8}$

= $(\frac{2}{4}+\frac{3}{4})$ ÷ $\frac{1}{8}$

= $(\frac{5}{4})$ ÷ $\frac{1}{8}$

= $(\frac{5}{4})$ x $\frac{8}{1}$

= $\frac{40}{4}$

= 10

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2 years ago

A manufacturer of prefabricated homes has decided to subcontract four components of the homes. Several companies are interested

Xelga [282]

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Let $x_{ij}=1$ when i is the element itself is allocated to 'j' $i_0$

Min

$185X_{1A}+225X_{1B} +193X_{1C} +207X_{1D} +200X_{2A} +190X_{2B} +175X_{2C}+225X_{2D}+330X_{3A} +320X_{3B} +315X_{3C}+300X_{3D}+375X_{4A}+389X_{4B}+425X_{4C}+ 445X_{4D}$

Subject to:

$X_{1A} +X_{1B}+X_{1C}+X_{1D}=1\\\\X_{2A} +X_{2B}+X_{2C}+X_{2D}=1\\\\X_{3A} +X_{3B}+X_{3C}+X_{3D}=1\\\\X_{4A} +X_{4B}+X_{4C}+X_{4D}=1\\\\X_{1A} +X_{2A}+X_{3A}+X_{4A}=1\\\\X_{1B} +X_{2B}+X_{3B}+X_{3B}=1\\\\X_{1C} +X_{2C}+X_{3C}+X_{4C}=1\\\\X_{1D} +X_{2D}+X_{3D}+X_{4D}=1$

4 0

3 years ago

When applying for a loan, you should _____.

ivanzaharov [21]

You should also have a little money saved aside so that you can pay them the money you saved and then work for the rest of the money you need to pay off

sorry if im incorrect

5 0

2 years ago

A student records the repair cost for 22 randomly selected dryers. A sample mean of $98.78 and standard deviation of $15.49 are

Gelneren [198K]

Answer:

The critical value that should be used is T = 2.0796.

The 95% confidence interval for the mean repair cost for the dryers is between $91.912 and $105.648.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 22 - 1 = 21

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 21 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 2.0796, which is the critical value that should be used.

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2.0796\frac{15.49}{\sqrt{22}} = 6.868$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 98.78 - 6.868 = $91.912

The upper end of the interval is the sample mean added to M. So it is 98.78 + 6.868 = $105.648

The 95% confidence interval for the mean repair cost for the dryers is between $91.912 and $105.648.

8 0

2 years ago