PLEASE HELP ME OUT 2 problems 40 points

Mathematics

1 answer:

babunello [35]4 years ago

5 0

Answer:c the way you do you send it over and then send

Step-by-step explanation:

was the only one I got for the day I got a little bit more to get a good

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Brian flips a fair coin 3 times. What is the probability of getting 3 tails?

Sliva [168]

Answer:

the answer is one over eight

the formula says required outcome divided by sample space

the sample space here is it because we have three coins and the Three coins have two faces each so it becomes 2 x 2 * 2 that is 8 and that is the total sample space we are supposed to get the probability of getting 3 tails and for each coin you have 1/2 x 1/2 x 1/2 and that is 1/8 as your final answer and do probability of getting three tails

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Mentally find the distance between the two values on a number line 70 and 70

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4 years ago

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Jobisdone [24]

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3 years ago

12n^3 + 16n^3 can someone please help me with this?

vodka [1.7K]

Answer:

$4n^{3} (3n^{2} + 4)$

Step-by-step explanation:

Assuming the problem is asking you to factor out the formula, it can be done easily by finding a common number with the two givens.

4 goes into both 12 and 16 evenly, so we will use this to factor. But that's not all, we have the n-variable to worry about.

Look at the n-variable exponents in the problem, take the highest power that can go be subtracted from both and use that. We have a $n^{5}$ and $n^{3}$ . Since 5 can't go into 3, we must use 3 to factor.

Our factoring variable will therefore be $4n^{3}$ . Now, use this to simply divide and get the answer:

$( 12n^{5} + 16n^{3} ) / 4n^{3} = 4n^{3}(3n^{2} + 4)$

So how did we get this? For the whole numbers, we have to divide: (12/4, 16/4). Next, we have to minus the exponents since we are dividing.

When dividing the 12 and 4, minus the $n^{5}$ and $n^{3}$ to get $n^{2}$ . Get rid of the $n^{3}$ term for the 16 and leave the 4. And there's your answer!