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Kruka [31]
3 years ago
5

Mark is playing a trivia game. On his first turn, he lost 100 points. On his second turn, he lost 55 points. On his third turn,

he lost 65 points. Enter a sum that models the change to Mark's score after his first three turns. HELPP!!!!!! WORTH 15 POINTSS
Mathematics
2 answers:
den301095 [7]3 years ago
8 0
I swear you just add 100 55 and 65
MrMuchimi3 years ago
3 0

It’s easier to take this question step-by-step.

Mark starts with 0 points.

Since he loses 100 points on his first turn, we can subtract.

0 - 100 = -100

From there, he loses another 55 points, meaning we subtract that from his first-turn total.

-100 - 55 = -155

On his third turn, he loses another 65 points, so we subtract from his second-turn total.

-155 - 65 = -220

Therefore, Mark’s total points at the end of three turns is -220.

Hopefully this helps! :)

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Answer: 72

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3. In an auditorium, 1/6 of the students are fifth graders, 1/3 are fourth graders, and 1/4 of the remaining students are second
Katen [24]

12

<h3>Further explanation</h3>

<u>Given:</u>

In an auditorium,

  • \frac{1}{6} of the students are fifth graders,
  • \frac{1}{3} are fourth graders, and
  • \frac{1}{4} of the remaining students are second graders.

There are 96 students in the auditorium.

<u>Question:</u>

How many second graders are there?

<u>The Process:</u>

The least common multiple (LCM) of 3 and 6 is 6.

Let us draw the diagram of all students.

96 \div 6 \ units = 16 \rightarrow \boxed{16}\boxed{16}\boxed{16}\boxed{16}\boxed{16}\boxed{16} = 96 \ students

  • \frac{1}{6} of the students are fifth graders, or 1 of 6 units above, that is \boxed{16} = 16 \ students
  • \frac{1}{3} = \frac{2}{6} are fourth graders, or 2 of 6 units above, that is \boxed{16}\boxed{16} = 32 \ students

The remainder is 6 units - (1 unit + 2 units) = 3 units, that is \boxed{16}\boxed{16}\boxed{16} = 48 \ students. Or, 96 - 16 - 32 = 48 students.

\frac{1}{4} of the remaining students are second graders.

Let us count how many second graders are there.

\boxed{ \ \frac{1}{4} \times 48 \ students = ? \ }

Thus, there are 12 second-graders in the auditorium.

- - - - - - - - - -

Quick Steps

\boxed{ \ \frac{1}{4} \times \bigg(1 - \frac{1}{6} - \frac{1}{3} \bigg) \times 96 = ? \ }

\boxed{ \ = \frac{1}{4} \times \bigg(\frac{6}{6} - \frac{1}{6} - \frac{2}{6} \bigg) \times 96 \ }

\boxed{ \ = \frac{1}{4} \times \frac{3}{6} \times 96 \ }

\boxed{ \ = \frac{3}{24} \times 96 \ }

We crossed out 24 and 96.

\boxed{ \ = 3 \times 4 \ }

\boxed{\boxed{ \ = 12 \ students \ }}

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Keywords: In an auditorium, 1/6 of the students, fifth graders, 1/3, fourth, 1/4, the remaining students, second, 96, how many, second graders

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Answer:

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Step-by-step explanation:

Because it lost 3 cm out of 10 which is 30%.

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