This question is simply asking you to find the x and y intercepts, which can be found by taking y as zero & x as zero, respectively. These intercepts are points that cross the x-axis or the y-axis. Consequently, by finding the intercepts you will be finding the values of A, B, C & D.
For example, to find values of A, B & C, you should note that they belong to the x-intercept, meaning you must put the value of y equal to zero (i.e y=0). Ultimately you will be solving for x, meaning you isolate x on its own to find its value.
Write the equation as it is helps as a starting point.
f(x)=y= | 3x + 1 | - 8 0 = | 3x + 1 | - 8 8 = | 3x + 1 | Since the x is enclosed inside the absolute value sign, an absolute value produces two values: one negative & the other positive, since a value or equation inside an absolute value sign CANNOT be negative.
Thus, 3x + 1 = 8 or 3x + 1 = -8. You must now solve the two equations.
3x + 1 = 8 3x = 7 x = 7/3
3x + 1 = -8 3x = -9 x = -3
Note that if you look at the value denoted by A, it is singular and in a whole form, whereas B & C make up one number, hinting that it is a quotient.
Therefore, A = -3 , B= 7, C = 3 (B/C= 7/3).
Hope this helped you! Try working out the y-intercept :)
The range is the difference between the biggest and smaller values of a set. The median is the middle value of a set. So we cannot say were the lowest score was found, comparing the median and ranges, because it could be that some repeated value very low or high is biasing the median, we could do it with the mean perhaps. So the proposal is false.
