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Bogdan [553]
4 years ago
8

How do you substitute 7x+2y=-19 and -x+2y=21

Mathematics
2 answers:
Kitty [74]4 years ago
8 0
Steps:
1. Take -x + 2y= 21
2. Add x on both sides
2y= x + 21
3. Divide everything by 2
Y= 1/2x + 10.5
4. Substitute the y in 7x + 2y= -19 for 1/2x + 10.5
7x + 2(1/2x + 10.5)= -19
5. Multiply everything in parentheses
7x + x + 21= -19
8x + 21= -19
6. Subtract 21 on both sides
7. 8x=-40
8. Divide each side be 8
9. Your answer is
X=-5
mina [271]4 years ago
6 0
It's easier to use -x +2y = 21
so make it all = to x
should come out to x= 2y - 21
now substitute what you just found = to x into the other equation
7 (2y - 21) + 2y = - 19
now distribute and simplify
14y - 147 + 2y = -19
16 y = 128
y = 8

now substitute 8 for y in either equation
-x + 2( 8) = 21
-x = 5
x = -5


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7 0
4 years ago
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alekssr [168]

Hello from MrBillDoesMath!

Answer:

3

Discussion:

34           + 2x = 40             => subtract 34 from both sides

(34-34)   + 2x = 40 - 34     => as (34-34) = 0 and 40-34 = 6

2x                   = 6               => divide both sides by 2

x = 6/2 = 3

Check the answer:

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Does 34 + 6      = 40 ?  YES! so the answer checks.

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4 0
3 years ago
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Answer:

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the answer is 9xy2 – 6x2y + 5x3

Step-by-step explanation:

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Is there a picture along with the question?
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Prime numbers can only be divisible by 1 and itself.
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