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NISA [10]
3 years ago
5

What is the square root of 28x to the third power y to the third power

Mathematics
1 answer:
Colt1911 [192]3 years ago
6 0

Hello!

√28x³y³ is equal to 2xy\sqrt{7xy}

We can find this solution through the following steps.

  1. Rewriting the equation by factoring 4 from 28, factoring out x², and factoring out y²
  2. We then can rewrite 4 as 2² in our equation, leaving us with \sqrt{2^{2}*7*(x^{2}x)*y^{2}y }
  3. We will then move our x and 7, and rewrite 2^{2}*x^{2}* y^{2} as (2xy)^{2}
  4. We can then pull the terms from the radical leaving us with 2xy\sqrt{7xy}
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5 0
3 years ago
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4 is subtracted from r
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Algebraic expression ;

r-4

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