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saul85 [17]
3 years ago
10

What is the value of x in 34 + 2x = 40

Mathematics
2 answers:
alekssr [168]3 years ago
4 0

Hello from MrBillDoesMath!

Answer:

3

Discussion:

34           + 2x = 40             => subtract 34 from both sides

(34-34)   + 2x = 40 - 34     => as (34-34) = 0 and 40-34 = 6

2x                   = 6               => divide both sides by 2

x = 6/2 = 3

Check the answer:

Does 34 + 2x = 40 if x = 3 ?

Does 34 + 2(3) = 40 ?

Does 34 + 6      = 40 ?  YES! so the answer checks.

Thank you,

MrB

Varvara68 [4.7K]3 years ago
3 0
Yes it is 6 like he said above
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3 years ago
What is the equation of the line graphed below?
vesna_86 [32]

Answer:

The answer to your question is: letter B

Step-by-step explanation:

Data

A (-5, 4)

B (4, 1)

Formula

slope  = m = \frac{1 - 4}{4 + 5}

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Point slope

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3 years ago
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6 0
3 years ago
X^2+4x+y^2-10y+20=30 find the center of the circle by completing the square
swat32

Answer:

a). Center of the circle = (-2, 5)

b). Equation of the line ⇒ y = -\frac{4}{5}x+\frac{58}{5}

Step-by-step explanation:

Equation of the circle is,

x² + 4x + y²- 10y + 20 = 30

a). [x² + 2(2)x + 4 - 4] + [y²- 2(5)y + 25] - 25 + 20 = 30

   [x² + 2(2)x + 4] - 4 + [y² - 2(5)y + 25] - 25 + 20 = 30

   (x + 2)² + (y - 5)²- 29 + 20 = 30

   (x + 2)² + (y - 5)²- 9 = 30

   (x + 2)² + (y - 5)² = 39

By comparing this equation with the standard equation of a circle,

    Center of the circle is (-2, 5).

b). A point (2, 10) lies on this circle.

    Slope of the line joining this point to the center (-2, 5),

    m_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

          = \frac{10-5}{2+2}

          = \frac{5}{4}

    Let the slope of the tangent which is perpendicular to this line is 'm_{2}'

    Then by the property of perpendicular lines,

          m_{1}\times m_{2}=-1

          \frac{5}{4}\times m_{2}=-1

                 m_{2}=-\frac{4}{5}

   Now the equation of the line passing though (2, 10) having slope m_{2}=-\frac{4}{5}

           y - y' = m_{2}(x-x')

           y - 10 = -\frac{4}{5}(x-2)

           y - 10 = -\frac{4}{5}x+\frac{8}{5}

                  y = -\frac{4}{5}x+\frac{8}{5}+10

                  y = -\frac{4}{5}x+\frac{58}{5}

Therefore, equation of the line will be, y = -\frac{4}{5}x+\frac{58}{5}

7 0
3 years ago
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