Answer:
Step-by-step explanation:
From the first sentence x (the number) is 2 more than another number (y). So, x+2=y. The sum of the squares of the two numbers is 42, meaning that 
+
=42. First, we square root the ENTIRE equation to get rid of the square. If you do one thing to one side, you have to do it to the other. After this, we have x+2+y=
. Now, we subtract 2 from the other side to isolate the variable. You can isolate either one but normally I go for x. Now we have x+y=+2. Now, we want to get y to the other side so we subtract it from the left side and the right side which gives us x=-y++2. now we know what X is equal to. Now we plug in x for +=42, which gives us 
+=42. Now we only have one variable which is what we want. Next, we square root the entire thing to get rid of the squares, which gives us -y++4+y=. I got lost in my work. I must have done something wrong I cant find out. If anyone wants to pick up where I left off go ahead but there's a timer and I have one minute left. I cant finish the problem in a minute. I'm sorry and hopefully I lead you somewhere.
Measures change in price levels of market s
If you understand what is linear pair, you can see the same in triangle also. A linear pair is a pair of adjacent, supplementary angles. Adjacentmeans next to each other, and supplementary means that the measures of the two angles add up to equal 180 degrees.
Answer:
30
Step-by-step explanation:
5ab-2c
5(2)(3)-2(0)
5(6)-2(0)
30-0
30
The line y = x + 3 has slope 1, so we look for points on the curve where the tangent line, whose slope is dy/dx, is equal to 1.
y² = x
Take the derivative of both sides with respect to x, assuming y = y(x) :
2y dy/dx = 1
dy/dx = 1/(2y)
Solve for y when dy/dx = 1 :
1 = 1/(2y)
2y = 1
y = 1/2
When y = 1/2, we have x = y² = (1/2)² = 1/4. However, for the given line, when y = 1/2, we have x = y - 3 = 1/2 - 3 = -5/2.
This means the line y = x + 3 is not a tangent to the curve y² = x. In fact, the line never even touches y² = x :
x = y² ⇒ y = y² + 3 ⇒ y² - y + 3 = 0
has no real solution for y.
