Answer:
a. p(x<= 5) = .15 + .4 + .25 = .8
C. .4(4.2) = 1.68
5.4(1-.4) = 3.24
3.24 + 1.68 = 4.92 ,, 4.92 > 4.55 so short is better
Step-by-step explanation:
Here i how I would do it:<span>f(x)=−<span>x2</span>+8x+15</span>
set f(x) = 0 to find the points at which the graph crosses the x-axis. So<span>−<span>x2</span>+8x+15=0</span>
multiply through by -1<span><span>x2</span>−8x−15=0</span>
<span>(x−4<span>)2</span>−31=0</span>
<span>x=4±<span>31<span>−−</span>√</span></span>
So these are the points at which the graph crosses the x-axis. To find the point where it crosses the y-axis, set x=0 in your original equation to get 15. Now because of the negative on the x^2, your graph will be an upside down parabola, going through<span>(0,15),(4−<span>31<span>−−</span>√</span>,0)and(4+<span>31<span>−−</span>√</span>,0)</span>
To find the coordinates of the maximum (it is maximum) of the graph, you take a look at the completed square method above. Since we multiplied through by -1, we need to multiply through by it again to get:<span>f(x)=31−(x−4<span>)2</span></span><span>
Now this is maximal when x=4, because x=4 causes -(x-4)^2 to vanish. So the coordinates of the maximum are (4,y). To find the y, simply substitute x=4 into the equation f(x) to give y = 31. So it agrees with the mighty Satellite: (4,31) is the vertex.</span>
Answer:
21/4 :3/4= 21/4 *4/3= 7/1 *1/1 = 7
7 bookcases
Step-by-step explanation:
The two parallel bases b1 and b2 are
b1 = 12
b2 = 9
the order of which base you pick doesn't matter
The height is h = 10 and it's perpendicular to each base.
The area is...
A = (1/2)*h*(b1+b2)
A = (1/2)*10*(12+9)
A = (1/2)*10*(21)
A = 5*21
A = 105
Final Answer: B) 105 square centimeters
Answer:
Step-by-step explanation:
![\sf 3(t+3)+5(3+2t)-76 = 0\\\\Expanding \ Parenthesis\\\\3t + 9 + 15 + 10t -76 = 0\\\\13t + 24 -76 = 0\\\\13t - 52 = 0\\\\Add \ 52 \ to \ both \ sides\\\\13t = 52\\\\Dividing\ both\ sides\ by\ 13\\\\t = 52/13\\\\t = 4\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%203%28t%2B3%29%2B5%283%2B2t%29-76%20%3D%200%5C%5C%5C%5CExpanding%20%5C%20Parenthesis%5C%5C%5C%5C3t%20%2B%209%20%2B%2015%20%2B%2010t%20-76%20%3D%200%5C%5C%5C%5C13t%20%2B%2024%20-76%20%3D%200%5C%5C%5C%5C13t%20-%2052%20%3D%200%5C%5C%5C%5CAdd%20%5C%2052%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5C13t%20%3D%2052%5C%5C%5C%5CDividing%5C%20both%5C%20sides%5C%20by%5C%2013%5C%5C%5C%5Ct%20%3D%2052%2F13%5C%5C%5C%5Ct%20%3D%204%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
