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nikdorinn [45]
3 years ago
12

Roads in urban areas are generally ___.

Computers and Technology
2 answers:
Ksju [112]3 years ago
4 0

Answer:

D is the answer

Explanation:

Urban roads tend to be wider. Sometimes they are more interesting, but that does not always have to be the case. D

They are usually paved, especially in Canada and the United States. I have not seen very many urban roads that are not paved, even those of the edge of the urban areas. Not C. Not B either.

Few are narrow although there are exceptions. White Avenue in Edmonton Alberta is 4 lanes but it still seems narrow to me. It is very interesting however.  Not A

choli [55]3 years ago
4 0

Answer:

a

Explanation:

In urban areas, the roads themselves are generally narrower and more compact due to the inherent density of urban infrastructure and planning. This requires precision driving in dense traffic.

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legacy application that has hard-coded static IP addresses and is running on an EC2 instance, what is the best failover solution
AlladinOne [14]

Answer:

Elastic IP address

Explanation:

Elastic IP addresses are static, persistent public IP addresses which can be associated and disassociated with the instance, as required.

This will provide the best failover solution that will keep same IP address on a new instance.

6 0
4 years ago
In the 2018-2019 softball season, Allison hit the ball 28 out of 67 times, this included fouls. What was her percentage
ruslelena [56]

Answer:

Allison missed 58.21% of the times.

Explanation:

The first step is to divide 28 by 67 to get the answer in decimal form:

28 / 67 = 0.4179

Then, we multiplied the answer from the first step by one hundred to get the answer as a percentage:

0.4179 * 100 = 41.79%

Then 100(%) - 41.79(%) = 58.21%

5 0
3 years ago
Consider the following definition of a recursive method. public static int mystery(int[] list, int first, int last) { if (first
ozzi

Answer:

c. 27

Explanation:

  • In recursion method, a method calls itself until a condition becomes true and returned back. In mystery(), at first time, first is 0 and last is 4. Condition is checked and 0!=4 so else part is executed in which again mystery is called with first as 1 and last 4. This will go again and again until first=4.
  • When first=4 it is also equal to last so if part is executed and alpha[4] is returned which is 9, now it comes alpha[3] +9 which is 8+9 =17 .
  • It is returning values to its previous calls that is why it will reduce to alpha[0]+alpha[1]+alpha[2]+17 which is nothing but sum of all elements of a alpha
  • Then, 1+4+5+8+9=27.
5 0
3 years ago
The celestial sphere is divided into
7nadin3 [17]

Answer:

A.

Explanation:

4 0
3 years ago
Read 2 more answers
On a keyboard num lock and caps lock are both toggle keys. <br> a. True <br> b. False
tekilochka [14]
The answer is a) True
6 0
4 years ago
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