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Snezhnost [94]
3 years ago
9

Sequence encryption is a series of encryptions and decryptions between a number of systems, wherein each system in a network dec

rypts the message sent to it and then reencrypts it using different keys and sends it to the next neighbor. This process continues until the message reaches the final destination.
a. True
b. False
Computers and Technology
1 answer:
valentina_108 [34]3 years ago
3 0

Answer:

The answer is True.

Explanation:

In a Network data transfer, it is essential for the security purpose that data should be in encrypted form which an unreadable form and it will be decrypted when it reaches the destination system.

It is important for the organization to encrypt data to make it safe from hackers and cryptographic technology is used in data Sequence encryption.

There is a key that is used to decrypt data in the network system and encryption and decryption is a sequential process for the data starting from the initial system and ending in the destination system.

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If a speed mismatch was configured between two Cisco routers' Ethernet interfaces, what would the status of this interface be?
noname [10]

Answer:

Down/down is the correct answer.

Explanation:

The down/down is the status of the interface when the speed of the ethernet mismatches that is configuration between the Cisco routers. Generally, it is the way of saying by the Cisco is "the connection" or the following ports are available for the connection but do not have one of them then, check their systems or the cables connection.

5 0
3 years ago
WHICH OF THESE IS A TYPE OF ETHERNET <br> 802.11AC <br> 1000BASET <br> 4G
Kobotan [32]

Answer:

1000BaseT

Explanation: Just took the quiz and got it right!

1000BaseT is specific to Ethernet

802.11ac is a type of WiFi connection (even though it uses Ethernet)

4G is what they use to provide cell phone service

6 0
3 years ago
What is software that helps a computer operate efficiently and keeps track of data on a computer?
Allisa [31]
<span>the answer is an operating system</span>
7 0
3 years ago
Write an application that instantiates five Recording objects and prompts the user for values for the data fields. Then prompt t
tangare [24]

Answer:

Here is the JAVA application

Recording.java:

class Recording {  //class name

String title;  //String type variable to store the title of the song

String artist;  //String type variable to store the artist name of the song

int playingTime;  //int type variable to store the playing time of the song in seconds  

public String getTitle() {  //accessor method to get the title of the song

   return title; }   //returns the current title of song

public void setTitle(String title) {  //mutator method to set the title of song

   this.title = title;  }   // sets the title of song

public String getArtist() {  //accessor method to get the artist name of the song

  return artist; }   //returns the current artist name of song

public void setArtist(String artist) {  //mutator method to set the artist name of song

  this.artist = artist; }   //sets the artist name

public int getPlayingTime() {  //accessor method to get the playing time of the song

   return playingTime; } /  /returns the playing time of song

public void setPlayingTime(int pt) {  //mutator method to set the playing time of song

   this.playingTime = pt; }   //sets the playing time of song

public Recording(String title, String artist, int playingTime) {  //parmeterized constructor of Recording class that takes title, artist and playingTime as parameters

this.title = title;  

this.artist = artist;

this.playingTime = playingTime;  }  }

Explanation:

Here is the Main class:  

import java.util.Scanner;   //to accept input from user

public class Main {  

public static void main(String[] args) {  // start of main function

 Recording[] song = new Recording[5];  //creates object of Recording class named song to instantiate five Recording objects

 Scanner input = new Scanner(System.in);  //creates Scanner class object named input

 int i = 0;  // declare i and initialize it to -

 for (i = 0; i < song.length; i++) {  //iterates through the list of song

  int j = i + 1;  

  System.out.print("Enter the title of song " + j + ": ");  //prompts user to enter the title of song

 String title = input.nextLine();   //reads the title string from user

 System.out.print("Enter the artist of song " + j + ": ");  //prompts user to enter the artist of song

 String artist = input.nextLine();   //reads the artist string from user

System.out.print("Enter the playing time of song " + j + " in seconds: ");   //prompts user to enter the playing time of song

 String playtime = input.nextLine();  //reads the playing time string value from user

 int playingTime = Integer.parseInt(playtime);   // converts String value of playtime to integer

 song[i] = new Recording(title, artist, playingTime); }   //calls constructor of Recording class by passing title, artist and playingTime to it  

 int sort;  // for choosing which field to sort

do {  //continues to ask user to enter which field the Recordings should be sorted by

System.out.println("How should these songs be sorted? 1 for title 2 for artist 3 for playing time");  

sort = input.nextInt();  //reads user choice to sort

       if (sort > 0 && sort < 4) {  //to check if user enters a valid choice

 int a, b;  

 int max = song.length - 1;  

for (a = 0; a < max; a++) {  //iterates through the length of the song list setting an index variable a

      for (b = 0; b < max; b++) {    //iterates through the length of the song list setting an index variable b

  int c = b + 1;

     if (sort == 1) {  //if the user selects title field

       if (song[b].getTitle().compareTo(song[c].getTitle()) > 0) {  // compares title of one song with the song that comes after it

   Recording temp = song[b];  //sorts the titles using bubble sort by ordering each title to the immediate next and swapping them if they are not sorted already

   song[b] = song[c];

   song[c] = temp; } }  

   else if (sort == 2) {    //if the user selects artist field

  if (song[b].getArtist().compareTo(song[c].getArtist()) > 0) {  // compares artist of one song with the song artist  that comes after it

//sorts the artists using bubble sort by ordering each title to the immediate next and swapping them if they are not sorted already

     Recording temp = song[b];

     song[b] = song[c];

     song[c] = temp;  }  }  

   else if (sort == 3) {   //if the user selects playing time field

  if (song[b].getPlayingTime() > song[c].getPlayingTime()) {

/* compares artist of one song with the song artist  that comes after it sorts the artists using bubble sort by ordering each title to the immediate next and swapping them if they are not sorted already */

       Recording temp = song[b];

        song[b] = song[c];

         song[c] = temp;  } } } }  }  

             else {  //if user enters any invalid choice

 System.out.println("Invalid choice! Enter right choice"); }        

       } while (sort < 1 || sort > 3);  //keeps asking user to enter which field the recording to sort by until the value of sort in range of 1 to 3

for (i = 0; i < song.length; i++) {  //displays the sorted song list according to selected field

System.out.println("Song: Title: " + song[i].getTitle() + ". Artist: " + song[i].getArtist() + ". Playing time: " + song[i].getPlayingTime() + " seconds.");  }

input.close();  }  }

The output of the program is attached.

7 0
3 years ago
Durante 10s, la velocidad de rotación y el momento de giro de las ruedas de un coche eléctrico son 100 rpm y 1405,92 Nm, respect
Akimi4 [234]

Answer:

c

Explanation:

hope this helps

6 0
3 years ago
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