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Snezhnost [94]
3 years ago
9

Sequence encryption is a series of encryptions and decryptions between a number of systems, wherein each system in a network dec

rypts the message sent to it and then reencrypts it using different keys and sends it to the next neighbor. This process continues until the message reaches the final destination.
a. True
b. False
Computers and Technology
1 answer:
valentina_108 [34]3 years ago
3 0

Answer:

The answer is True.

Explanation:

In a Network data transfer, it is essential for the security purpose that data should be in encrypted form which an unreadable form and it will be decrypted when it reaches the destination system.

It is important for the organization to encrypt data to make it safe from hackers and cryptographic technology is used in data Sequence encryption.

There is a key that is used to decrypt data in the network system and encryption and decryption is a sequential process for the data starting from the initial system and ending in the destination system.

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What kind of software consists of programs designed to make users more productive and/or assist them with personal tasks?
Sunny_sXe [5.5K]
It is application software
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3 years ago
The Zootopia Police Department is recruiting new officers and has come up with an innovative equation to hire. They define hireS
Dahasolnce [82]

Answer:

#include<iostream>

#include<limits>

#include<iomanip>

using namespace std;

//function that returns true

//if there is invalid input like giving string as input

// for integer value.

bool isInvalidInput()

{

  //return true if cin.fail

  if(cin.fail())

  {

      //clear the buffer

      cin.clear();

      cin.ignore(numeric_limits<streamsize>::max(),'\n');

      return true;

  }

  return false;

}

//function that calculates the hire score for given 3 parameters.

double calHireScore(double agility,double strength,double speed)

{

  return (1.8*agility) + (2.16 * strength) + (3.24 * speed);

}

//calculate hire score for fox.

void calFoxHireScore()

{

  double agility,strength;

 

  cout<<"Enter Agility Value: ";

  //get agility as input and validate it.

  cin >> agility;

  if(isInvalidInput() || agility <= 0)

  {

      cout<<"\nError: Agility value must be > 0"<<endl;

      return;

  }

 

  cout<<"Enter Strength Value: ";

  cin >> strength;

  if(isInvalidInput() || strength <= 0)

  {

      cout<<"\nError: Strength value must be > 0"<<endl;

      return;

  }

 

  cout<<"\nHire Score for Fox: "<<calHireScore(agility,strength,0)<<endl;

}

//function that asks input from user for

//calculating hire score for Sloth.

void calSlothHireScore()

{

  double strength,speed;

 

  cout<<"Enter Strength Value: ";

  cin >> strength;

  if(isInvalidInput() || strength <= 0)

  {

      cout<<"\nError: Strength value must be > 0"<<endl;

      return;

  }

 

  cout<<"Enter Speed Value: ";

  cin >> speed;

  if(isInvalidInput() || speed <= 0)

  {

      cout<<"\nError: Speed value must be > 0"<<endl;

      return;

  }

 

  cout<<"\nHire Score for Sloth: "<<calHireScore(0,strength,speed)<<endl;

}

//function that asks input from user for

//calculating hire score for Bunny.

void calBunnyHireScore()

{

  double agility,speed;

 

  cout<<"Enter Agility Value: ";

  cin >> agility;

  if(isInvalidInput() || agility <= 0)

  {

      cout<<"\nError: Agility value must be > 0"<<endl;

      return;

  }

 

  cout<<"Enter Speed Value: ";

  cin >> speed;

  if(isInvalidInput() || speed <= 0)

  {

      cout<<"\nError: Speed value must be > 0"<<endl;

      return;

  }

 

  cout<<"\nHire Score for Bunny: "<<calHireScore(agility,0,speed)<<endl;

}

//function to display menu for user.

void menu()

{

  cout<<"\n1. Fox"<<endl;

  cout<<"2. Bunny"<<endl;

  cout<<"3. Sloth"<<endl;

  cout<<"0. Quit"<<endl;

  cout<<"Enter your choice: ";

}

//main method

int main()

{

  int choice;

  do

  {

      //asks choice

      menu();

      cin >> choice;

      //if invalid input print erro message

      if(isInvalidInput())

      {

          cout<<"\nError: Invalid choice enetered. Try Again\n";

      }

      else

      {

          cout<<"\n";

          //if any one of the choices do accordingly

          //for invalid choice print error mesage.

          switch(choice)

          {

              case 1:

                  calFoxHireScore();

                  break;

              case 2:

                  calBunnyHireScore();

                  break;

              case 3:

                  calSlothHireScore();

                  break;

              case 0:

                  cout<<"\nQutting...\n";

                  break;

              default:

                  cout<<"Invalid choice entered."<<endl;

                  break;

          }

      }

     

  }while(choice != 0);

 

  return 0;

}

Explanation:

3 0
4 years ago
Your company has 1,000 users in a Microsoft Office 365 subscription. A Power BI administrator named Admin1 creates 20 dashboards
AysviL [449]

Answer:

Yes, it is.

Explanation:

Yes it will surely achieve the goal. When there is no license for user, then he/she will not access the dashboard.

7 0
3 years ago
Explain vividly any operating system of your choice stating at least 3 distinguishing features of each version.
rosijanka [135]

Answer:

microsoft windows, macOS, and linux

Explanation:

if you need help let me know

7 0
3 years ago
Read 2 more answers
Write a program that reads whitespace delimited strings (words) and an integer (freq). Then, the program outputs the strings fro
Lesechka [4]

Answer:

See explaination for the code

Explanation:

def wordsOfFrequency(words, freq):

d = {}

res = []

for i in range(len(words)):

if(words[i].lower() in d):

d[words[i].lower()] = d[words[i].lower()] + 1

else:

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for word in words:

if d[word.lower()]==freq:

res.append(word)

return res

Note:

First a dictionary is created to keep the count of the lowercase form of each word.

Then, using another for loop, each word count is matched with the freq, if it matches, the word is appended to the result list res.

Finally the res list is appended.

3 0
4 years ago
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